The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0
Thus, the equation of the trend line, in variables K and J, is
K = 2J + 28
Answer:
Factor:
x^2+5x-300=0
(x-15)(x+20)=0
x=15 is the width
x+5=20 is the length
Step-by-step explanation:
Standard form for the equation of the line is
Solution:
Given point is (2, –5).
slope of the line m = 
Here, 
Equation of a line passing through the point:
Subtract 15 from both sides of the equation.
Standard form for the equation of the line is
V=448 in^3
l=8 in
w=12
h=?
V=l•w•h/3
448=8•12•h/3 multiply both sides by 3
3•448=96•h
1344=96•h
h=1344/96
h=14 in
V=l•w•h/3
h=4in
l=3in
w=2.5 in
V=?
V=4•3•2.5/3
V=30/3
V=10 in^3
