Is this a right triangle?
2 answers:
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Answer:
(a)
(b)
<em>(b) is the same as (a)</em>
(c)
(d)
(e)
Step-by-step explanation:
Given
Solving (a): Probability of 3 or fewer CDs
Here, we consider:
This probability is calculated as:
This gives:
Solving (b): Probability of at most 3 CDs
Here, we consider:
This probability is calculated as:
This gives:
<em>(b) is the same as (a)</em>
<em />
Solving (c): Probability of 5 or more CDs
Here, we consider:
This probability is calculated as:
This gives:
Solving (d): Probability of 1 or 2 CDs
Here, we consider:
This probability is calculated as:
This gives:
Solving (e): Probability of more than 2 CDs
Here, we consider:
This probability is calculated as:
This gives:
3x -y ⩾ 6
3x - 6 ⩾ y
now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".
if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,
3(4) - 0 ⩾ 6
12 - 0 ⩾ 6
12 ⩾ 6
is 12 really greater or equals to 6? well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.
now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.
check the picture below.
3x - 6 ⩾ y
now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".
if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,
3(4) - 0 ⩾ 6
12 - 0 ⩾ 6
12 ⩾ 6
is 12 really greater or equals to 6? well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.
now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.
check the picture below.