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2 years ago

Find the area of the shape above

Mathematics

1 answer:

kirill115 [55]2 years ago

6 0

Answer:

625 cm^2

Step-by-step explanation:

Break it into a rectangle on the bottom and a triangle on top

rectangle area = 50 x 8 = 400 cm^2

triangle area = 1/2 b * h = 1/2 * 50 * 9 = 225 cm^2

added together = 625 cm^2

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Whitepunk [10]

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3 years ago

HELP Please <br> I don’t get it lol

weeeeeb [17]

Answer:

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Step-by-step explanation:

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3 years ago

A garden has 8 white roses and 11 red roses. One rose is plucked from the garden and then one more rose is plucked without repla

liberstina [14]

P(r/w) is the probability of picking a red rose at first picking and a white rose at second picking.
P(w/r) is the probability of picking a white rose at first picking and a red rose at second picking.

P(r/w) = $\frac{11}{19}$ × $\frac{8}{18}$ = $\frac{88}{342}$
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Notice that the second fraction is out of 18 because the second picking of rose will be out of 18 since the first rose is not replaced.

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3 0

4 years ago

-12<-6x please help

pishuonlain [190]

-12 < -6x

-12/-6 > x divide both sides by -6

12/6 > x two negatives makes a positive

2 > x simplify

x < 2 switch sides

hope this helps, God bless!

6 0

3 years ago

A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a

DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

$f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}$

Then the mean (first moment) is

$E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710$

and the second moment is

$E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3$

The second moment is useful in finding the variance, which is given by

$V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3$

You get the standard deviation by taking the square root of the variance, and so

$\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09$

8 0

3 years ago