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densk [106]
3 years ago
11

If bob had 4 apples and tim had 6 oranges but john had 4 times more oranges then tim but stephaine had 6 times more apples then

bob and jimmy had 4 bannanas and sid had to the power of 6 of what jimmy had
how many fruits would everyone have?
Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

Answer:

bob=4

tim=6

john=4x6=24

stephaine:24

jimmy=4

sid=1296

Step-by-step explanation:

so final answer 1358

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Answer: Hello!

Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)

We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.

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then P = 47! = 2.59e+59

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