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olga nikolaevna [1]
2 years ago
15

Please help me solve questions 1&2

Mathematics
1 answer:
zaharov [31]2 years ago
6 0

Answer:

1) Volume of prism is (V=Area of base×Height)

Volume " " "(V=22÷7×rsquare×h)

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3. The longer diagonal is 4 more than shorter diagonal of a kite. The areas times the shorter diagonal. If the shan side is 6 m
Phoenix [80]

Answer:

ehojggo5whkuegiyrgywtim csuo8teyi7

4 0
3 years ago
A particle begins at point (1, 2) and is moving along the line segment joining (1, 2) to (3, 4). Initially, what is the rate of
Bumek [7]

Answer:

Initially, that is, at (1,2), the rate of increase of the function in the direction given = 0

Hence the function is neither increasing nor decreasing initially in the given direction.

Step-by-step explanation:

f(x,y) = 2x² - y²

Rate of Change of the function = ∇f = (fₓ, fᵧ)

And we're told to find the rate of change in a particular direction = ∇f.û

We first obtain the unit vector in that direction, û

Direction = (3,4) - (1,2) = (2,2)

Uni vector = vector/magnitude

Vector = 2î + 2j

magnitude = √(2² + 2²) = √8 = 2 √2

(2î + 2j)/(2√2) = (1/√2)î + (1/√2)j = û

Unit vector in the direction = (1/√2, 1/√2)

f = 2x² - y²

At (1,2)

fₓ = ∂f/∂x = 4x = 4

fᵧ = ∂f/∂y = -2y = -4

∇f = (4,-4)

∇f.û = (4î - 4j).((1/√2)î + (1/√2)j) = (4/√2) - (4/√2) = 0

If it was positive, then the function is increasing, if it was negative, the function is decreasing. Zero means neither of them.

Hence the function is neither increasing nor decreasing initially in the given direction.

7 0
2 years ago
If the measures of the angles of a quadrilateral are in the ratio of 3 : 4 : 5 : 8, find the measure (in degrees) of each angle.
BabaBlast [244]

Answer:

sorry just came here for the points

Step-by-step explanation:

6 0
2 years ago
Someone explain how this is answer C? Big points!
Snowcat [4.5K]

Answer:

C. x = 15 * sin 18°

Step-by-step explanation:

sin A = Opposite / Hypotenuse

sin 18° = x / 15

x = 15 * sin 18°

4 0
3 years ago
X = -2y + 300 3y = 800 - 4x
devlian [24]

Answer:

<h2>x = 140, y = 80</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}x=-2y+300&(1)\\3y=800-4x&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\3y=800-4(-2y+300)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\3y=800+(-4)(-2y)+(-4)(300)\\\\3y=800+8y-1200\\\\3y=8y-400\qquad\text{subtract}\ 8y\ \text{from both sides}\\\\-5y=-400\qquad\text{divide both sides by (-5)}\\\\y=80\\\\\text{Put it to (1):}\\\\x=-2(80)+300\\\\x=-160+300\\\\x=140

8 0
2 years ago
Read 2 more answers
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