Answer:
1
gradient =rise/run
Rise/run=4/4
4/4=1
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Given that the hyperbola has a center at (0,0), and its vertices and foci are on y-axis. This, the equation of the hyperbola is of the form
x²/a²-y²/b²=-1 (a>0, b>0)
In the equation, vertices are (0, +/-b) .
Thus,
b=60
Foci (0,+/-√(a²+b²))
thus
√(a²+60²)=65
hence solving for a²
a²=65²-60²
a²=625
a²=25²
hence the equation is:
x²/25²-y²/60²=-1
All of these answers are right
The correct answer is A. Jimmy is running late, so he starts to run to school but needs to take breaks.
Explanation:
The graph shows the distance in axis y and the time in axis x. Additionally, the graph presents different sections from A to E. In this, the sections A, C, and E show an increase in the distance from home, this implies there was movement. Moreover, the speed (distance traveled in time) is higher in sections C and E than in A because the distance increases in a shorter time. Also, in sections D and B there is no movement as time continues but the distance is the same. In this context, the description that best matches the graph is "Jimmy is running late, so he starts to run to school but needs to take breaks" because this is the only option that includes the breaks or lack of movement in sections B and D. Also, the changes in speed are likely to occur in this scenario.