Answer: P(odd) = 0.499
Step-by-step explanation:
Given:
Total number of people = 20
Number of men = 12
Number of women = 8
Number of jury to be selected = 6
For the jury to have an odd number of women. it must have either of the three.
1. 1 woman , 5 men
2. 3 women, 3 men
3. 5 women, 1 man
The total possible ways of selecting the 6 people jury is;
N = 20C6 = 20!/6!(20-6)!
N = 38760
The possible ways of selecting;
Case 1 : 1 woman, 5 men
N1 = 8C1 × 12C5
N1 = 8 × 792 = 6336
Case 2 : 3 women , 3 men
N2 = 8C3 × 12C3
N2 = 12320
Case 3 : 5 women, 1 man
N3 = 8C5 × 12C1
N3 = 672
P(Odd) = (N1+N2+N3)/N
P(odd) = (6336+12320+672)/38760
P(odd) = 19328/38760
P(odd) = 0.499
Answer:
7.8y - 26.2
Step-by-step explanation:
First expand:
Now combine like terms:
A coefficient is a number that is in front of an x. The number in front of the x squared term is 6.
So the answer is 6.
Answer:
Choice A, C and E
Step-by-step explanation:
<em>Your table is poorly presented</em>
Given
x y
First, we calculate the constant of proportionality (k)
For (3,1.47)
For (5,2.45)
For (9,4.41)
From the above calculations, the constant of proportionality is 0.49.
So, the usable rows must also have 0.49 as their constant of proportionality
<u>Choice A</u>
--- <em>This is usable</em>
<em />
<u>Choice B</u>
--- <em>This is not usable</em>
<em />
<u>Choice C</u>
--- <em>This is usable</em>
<em />
<u>Choice D</u>
---- <em>This is not usable</em>
<em />
<u>Choice E</u>
--- <em>This is usable</em>