To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate
400, because it is the hundreds place
Answer: 400
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The probability of you being the leadoff hitter is <span>8.3%.</span>
Explanation:
The number of possible rosters can be calculated with permutations, knowing that the coach can choose the first hitter among all 12 players, then the second hitter among the 11 players remaining and so on until the 9th hitter among the remaining 4 players.
Therefore:
Possible rosters = 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 = 79833600
The leadoff hitter is the first player in the batting order, therefore the number of possible rosters in which you are chosen as the first one is:
You leadoff = 1 <span>× 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 = 6652800
The probability of you being leadoff is:
P</span> = You leadoff / <span>Possible rosters
</span> = 6652800 / 79833600
= 1 / 12
= 0.08333
= 8.3%
Note that this is exactly the probability of you being chosen out of the 12 players of the team in a one-pick choice because it does not matter how the rest of the batting order is composed.
This is going to be a linear function. On the horizontal axis, you will have weeks. On the vertical axis will be weeks. The slope of the line is 6/1 = 6, since she plays 6 hrs/week. At week 0 (the y-axis), the value will be 8, since that is the initial number of hours played. Therefore, the equation is: f(x) = 6x+8 f(x) is # hours x = #'d weeks.
Answer:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Solution to the problem
Let X the random variable who represents the variable of interest. We know from the problem that the distribution for the random variable X is given by:
We select a sample of size n=64. That represent the sample size.
From the central limit theorem we know that the distribution for the sample mean is given by:
The mean for the sample distirbution would be given by:
And the deviation given by:
And then the distribution for the sample mean is: