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MrRa [10]
3 years ago
7

Answer pls (62+2) 4 - 10

Mathematics
1 answer:
jonny [76]3 years ago
6 0

Answer:

246

Step-by-step explanation:

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A town has a population of 6000 people in the year 2009 and is growing at a rate of 3% a year. Let t denote the time in years af
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Answer:

  • f(t) = 6000*1.03^t
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Step-by-step explanation:

The formula for exponential growth can be written a couple of different ways. One I prefer uses the problem numbers directly:

  population = (initial population) × (growth factor)^t

Here, the initial population is 6000, and the growth factor is 1+3% = 1.03. Then the function can be written as ...

  f(t) = 6000·1.03^t

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Another way to write the function is using the form ...

  f(t) = (initial population) × e^(kt)

where k is the natural logarithm of the growth factor. In this form, we have ...

  k = ln(1.03)

  k ≈ 0.0295588

so the function would be written ...

  f(t) = 6000·e^(0.0295588t)

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