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2 years ago

Determine the value of the variable. 5 + 17 = J - 14

Mathematics

2 answers:

BaLLatris [955]2 years ago

4 0

The variable value of 5 + 17 = J - 14 is 36

Step-by-step explanation :

5 + 17 = J - 14

move - 14 to the left side to 14

5 + 17 + 14 = J

add up the numbers

22 + 14 = J

36 = J

J = 36

_____________________

Nataly_w [17]2 years ago

3 0

You would add 5 and 17 and that would equal 22
Now it would be 22=J-14
Then add 14 on both sides so it cancels out 22 plus 14 is 36
So J would equal 36

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Evaluate V= bh divided by 3 for B= 9 in 2 and h=32 in

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It would be 96 because V=(9)(32)= 288/3=96

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3 years ago

Which is the graph of the inequality y ≥ 2x + 3

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2 years ago

The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili

Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean of a population is 74 and the standard deviation is 15.

This means that $\mu = 74, \sigma = 15$

Question a:

Sample of 36 means that $n = 36, s = \frac{15}{\sqrt{36}} = 2.5$

This probability is 1 subtracted by the pvalue of Z when X = 78. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{78 - 74}{2.5}$

$Z = 1.6$

$Z = 1.6$ has a pvalue of 0.9452

1 - 0.9452 = 0.0548

0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

Question b:

Sample of 150 means that $n = 150, s = \frac{15}{\sqrt{150}} = 1.2247$

This probability is the pvalue of Z when X = 77 subtracted by the pvalue of Z when X = 71. So

X = 77

$Z = \frac{X - \mu}{s}$

$Z = \frac{77 - 74}{1.2274}$

$Z = 2.45$

$Z = 2.45$ has a pvalue of 0.9929

X = 71

$Z = \frac{X - \mu}{s}$

$Z = \frac{71 - 74}{1.2274}$

$Z = -2.45$

$Z = -2.45$ has a pvalue of 0.0071

0.9929 - 0.0071 = 0.9858

0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c. A random sample of size 219 yielding a sample mean of less than 74.2

Sample size of 219 means that $n = 219, s = \frac{15}{\sqrt{219}} = 1.0136$

This probability is the pvalue of Z when X = 74.2. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{74.2 - 74}{1.0136}$

$Z = 0.2$

$Z = 0.2$ has a pvalue of 0.5793

0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

5 0

3 years ago

Manny used 8 tenth-size parts to model 8/10. Ana used fewer parts to model an equivalent fraction. How does the size of a part i

viktelen [127]

Alrighty, let's think of it like this: You are trying to fill a box with a bunch of sports balls. You have tiny little golf balls, and you have giant bowling balls. You need to fill this same box all the way up.

If you fill it with the tiny golf balls, you are going to need a whole lot of them!

If you are putting in bowling balls, only a few of them will fit, because they are so much bigger.

When it comes to your fraction, the box is the the number 8/10. That number will not change because we are not changing the size of the box.

We are just changing what we are filling it with. Manny, can fit 8 parts, or in this case balls, into the box.

It says Ana uses fewer parts, so she cannot fit as many in as Manny.

This means that Manny would have the golf balls, since he can fit more in than Ana, who must have the bowling balls.

So which is bigger? A bowling ball or a golf ball?

A bowling ball, which is what Ana has. So Ana's part will be bigger in size.

4 0

2 years ago

Read 2 more answers

Please help me!

yan [13]

Answer:

Step-by-step explanation:

A = Area of First Rectangle 

B = Area of Second Rectangle 

w = Width

12(w)=320+B (1st Equation)

8(w) = B (2nd Equation)

w=B/8 (Plug this value of w into the first equation)

12B/8 = 320 +B (you get this)

12B= 2560 + 8B (Simplify)

4B = 2560

B =640 plug this value into the 2nd equation

8(w) = 640

w = 80

To Test This

12x80 = 960

8x80 = 640

<h3>960 - 640 = 320 Therefore the answer is correct the width is 80</h3>

<h3 />

5 0

2 years ago