Answer:
The quadratic equation is x^2 -12x -120 = 0
where x represents the length of the field
Step-by-step explanation:
We want to make an expression in terms of a quadratic equation;
Let the length of the field be x mm , then the width will be (x-12) mm
Mathematically , the area of the field will be L * B
Thus;
x * (x-12) = 120
That gives;
x^2 -12x = 120
x^2 -12x -120 = 0
If the diameter is 16 inches, then its radius is half that, r = 8.
Answer:
- x = -1/2(1 +√21) ≈ -2.79129
- x = -1/2(1 -√21) ≈ 1.79129
Step-by-step explanation:
We assume the middle term is supposed to be 4x.
We can remove a common factor of 4 to simplify this a bit.
x^2 +x -5 = 0
This is of the form
ax^2 +bx +c = 0
where a=1, b=1, c=-5.
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The <em>quadratic formula</em> gives the solutions as ...

Filling in the given coefficients, we have ...
x = (-1 ±√(1^2 -4·1·(-5)))/(2·1)
x = (-1±√21)/2
The solutions are x = -1/2(1 +√21) and -1/2(1 -√21).
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<em>If what you wrote is what you intend</em>, then the equation simplifies to 4x^2 -16 = 0.
Dividing by 4 and factoring the difference of squares gives ...
x^2 -4 = 0
(x -2)(x +2) = 0
These factors are zero (hence their product is 0) for the values x = 2 and x = -2.
The solutions are x=2 and x=-2.
Answer:
7a ( 1,1)
7b ∅ or no solution
Step-by-step explanation:
The solution to the system is where the two functions intersect
For 7a. The parabola and the line intersect at (1,1)
For 7b The parabola and the line do not intersect so there is no solution