If ray EB bisects angle AEC, then m∠AEB=m∠BEC=4x+1.
Angles AEB, BEC and CED together form right angle AED, then
m∠AEB+m∠BEC+m∠CED=90°.
Therefore,
(4x+1)+(4x+1)+3x=90,
11x=90-2,
11x=88,
x=88:11,
x=8°.
Then m∠BEC=4x+1=4·8+1=33°.
Answer: x=8°, m∠BEC=33°.
Answer:
a and b are parallel and its alternate interior angles
Answer:
11+6=17
Step-by-step explanation:
The answer is 9m v=x^3=729
x^3=9^3
x=9m
Since I'm kind of confused about the question, this may not be right. However, the answer I got from the info in the question is 19/60. I'm sorry if it's wrong.