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ivann1987 [24]
3 years ago
7

Which value of x makes the following equation true?

Mathematics
1 answer:
alekssr [168]3 years ago
5 0

Answer:

The value of x that will make this equation true is 50.

0.5 times 50=25 -8 = 17

0.2 times 50= 10 +7 = 17

Therefore, your answer is 50.

Step-by-step explanation:

Know ur meme ;)

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Which equation could define the function below?
dimulka [17.4K]

Answer:

y= (x+1)(x+ .5) (x+ 3.5)

y= (x+1) (X - .5) (x-3.5)

y = (x-1) (X-.5) (x-3.5)

y= (x+1) (X- .5) (x +3.5)

Step-by-step explanation:

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2 years ago
What is the volume of a right circular cone if the circumference of the base is 125.6 ft and the height is 75 ft.? Use π=3.14 an
Alex_Xolod [135]

Answer:

The volume of a right circular cone is 31400\ \text{feet}^3.

Step-by-step explanation:

The circumference of the base of a right circular cone is 125.6 ft.

Height of cone is 75 ft.

Circumference of base is :

C=2\pi r, r is radius

r=\dfrac{C}{2\pi}\\\\r=\dfrac{125.6}{2\times 3.14}\\\\r=20\ ft

The volume of a cone is given by :

V=\dfrac{1}{3}\pi r^2 h\\\\V=\dfrac{1}{3}\times 3.14\times (20)^2\times 75\\\\V=31400\ \text{feet}^3

So, the volume of a right circular cone is 31400\ \text{feet}^3.

5 0
3 years ago
Kate is making pizza she put 8 ounces of cheese on each pizza if she has 4 20ounce packages of cheese how many pieces can she ma
dexar [7]

Answer:

60 pizzas


Step-by-step explanation:


4 0
3 years ago
Jose earned 15 points in a video game. He lost 40 points, earned 87 points, then lost 30 more points. Write and evaluate an expr
KIM [24]

(15-40)+(87-30)

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32 total points

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3 years ago
How are central tendency and standard deviation related
loris [4]

Answer:

Measure of central tendency is a value that represents a typical, or central, entry of a data set. The most common measures of central tendency are: • Mean (Average): The sum of all the data entries divided by the number of entries. ... The standard deviation measure variability and consistency of the sample or population.

Step-by-step explanation:

5 0
3 years ago
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