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pishuonlain [190]
3 years ago
13

Solve for x. 30 18 х A. 35 B. 32 OC. 22 D. 24

Mathematics
1 answer:
Nikitich [7]3 years ago
4 0

Answer:

option d is the correct answer

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Step-by-step explanation:

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3 years ago
Evaluate the following expression will give branliest<br> 256 to the power of 5/8
Nana76 [90]

Answer:

32

Step-by-step explanation:

The formula needed to solve this question by hand is:

x^{\frac{m}{n}} =\sqrt[n]{x^{m}}

256^(5/8) = 8th root of 256^5

256^(5/8) = 8th root of 1280

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5 0
3 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs. Find the distance between each pair of points. 5 units 4 units 2 unit
Olin [163]

Answer:

a) Distance between points A (5, 4) and B( 5, -2) is 6 units

b) Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) Distance between points G(3, -5) and H(6, -5) is 3 units

Step-by-step explanation:

We need to find the distance between each pair

a) A (5, 4) and B( 5, -2)

the distance formula is:

d(A,B) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Putting values: x₁ = 5, x₂=5 and y₁= 4 and y₂= -2

d(A,B) = \sqrt{(5-5)^2+(-2-4)^2}

d(A,B) = \sqrt{(0)^2+(-6)^2}

d(A,B) = \sqrt{36}

d(A,B) = 6

Distance between points A (5, 4) and B( 5, -2) is 6 units

b)  E (-2, -1) and F( -2, -5)

the distance formula is:

d(E,F) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Putting values: x₁ = -2, x₂=-2 and y₁= -1 and y₂= -5

d(E,F) = \sqrt{(-2-(-2))^2+(-5-(-1))^2}

d(E,F) = \sqrt{(0)^2+(-4)^2}

d(E,F) = \sqrt{16}

d(E,F) = 4

Distance between points E (-2, -1) and F( -2, -5) is 4 units

c)  C (-4, 1) and D( 1, 1)

the distance formula is:

d(C,D) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Putting values: x₁ = -4, x₂=1 and y₁= 1 and y₂= 1

d(C,D)= \sqrt{(1-(-4))^2+(1-(1))^2}

d(C,D) = \sqrt{(5)^2+(0)^2}

d(C,D) = \sqrt{25}

d(C,D) = 5

Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) G(3, -5) and H(6, -5)

the distance formula is:

d(G,H) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Putting values: x₁ = 3, x₂=6 and y₁= -5 and y₂= -5

d(G,H)= \sqrt{(6-(3))^2+(-5-(-5))^2}

d(G,H) = \sqrt{(3)^2+(0)^2}

d(G,H) = \sqrt{9}

d(G,H) = 3

Distance between points G(3, -5) and H(6, -5) is 3 units

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3 years ago
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Find the gradient of the line 2y = 8x + 1 =
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56 46 38 2 12

Step-by-step explanation:

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4 years ago
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