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2 years ago

Solve for x. 30 18 х A. 35 B. 32 OC. 22 D. 24

Mathematics

1 answer:

Nikitich [7]2 years ago

4 0

Answer:

option d is the correct answer

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suppose you are in your last semester of college and have a 2.75 GPA after 105 credit hours if you are taking 15 credit hours in

Valentin [98]

Answer:

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

Step-by-step explanation:

Given,

CGPA = 2.75

Credit hours = 105

Last semester GPA = 4

Last semester credit hours = 15

CGPA = $\frac{sum of (Credit hours of each subject * GPA of each subject)}{Total credit hours}$ credit hours * gpa

in our case, it would be:

CGPA = $\frac{(2.75*105)+(4*15}{105+15}$

=> $\frac{(288.75)+(60)}{120}$

=> $\frac{348.75}{120}$

=> 2.90

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

7 0

3 years ago

Marvin marked off the ground for a rectangular garden. The garden was to have an area represented by the polynomial expression 2

mafiozo [28]

Answer: 621

Step-by-step explanation: 28^2+ 13 − 176

length, width, and height.

8 0

2 years ago

Another easy one

andreyandreev [35.5K]

The limit is equivalent to the value of the derivative of $\cos x$ at $x=\dfrac\pi2$ . (See definition of derivative)

$(\cos x)'=-\sin x\implies (\cos x)'\bigg|_{x=\pi/2}=-\sin\dfrac\pi2=-1$

4 0

2 years ago

Y = x² + 6x + 3

olganol [36]

Vertex is at $\left(-3,-6\right)$

y-intercept is 3.

The parabola opens up.

Step-by-step explanation:

The graph of the equation is hereby attached in the answer area.

Vertex is the point on the parabola where the graph crosses its axis of symmetry. The axis of symmetry here( $x =-3$ ), is shown with the dotted line in the graph attached.

y-intercept is defined as the value of y where the graph crosses the y-axis. In other words, when $x=0$ . Putting

And, the graph opens up as shown the graph figure as well. It is also evident from the co-efficient of $x$ in the given equation $y =x^{2} + 6x + 3$ . Here, co-efficient of