Answer:
16 quarts
Step-by-step explanation:
Let's say x is the volume of water.
Initially, the amount of antifreeze is the concentration times the volume: 0.90 (8).
After the water is added, the amount of antifreeze is the new concentration times the new volume: 0.30 (8 + x).
Since the amount of antifreeze doesn't change, we can set these equal and solve for x.
0.90 (8) = 0.30 (8 + x)
7.2 = 2.4 + 0.30 x
4.8 = 0.30 x
x = 16
16 quarts of water should be added.
The indicated partial derivative of z is; 1.
<h3>Partial derivatives</h3>
According to the question:
- We are required to determine the partial derivative of the variable z.
The given value of z is; Z = u, v, −w
Hence, it follows that;
d³z = ∂/∂u(u) + ∂/∂v(v) - ∂/∂w(w)
Ultimately, the value of ∂³z is; 1.
Read more on partial derivatives;
brainly.com/question/2293382
Answer:
Step-by-step explanation:
In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).
The formula we will use for this problem is the following:
where:
a=0
so the volume becomes:
This can be simplified to:
and the integral can be rewritten like this:
which is a standard integral so we solve it to:
![V=9\pi[tan y]\limits^\frac{\pi}{3}_0](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20y%5D%5Climits%5E%5Cfrac%7B%5Cpi%7D%7B3%7D_0)
so we get:
![V=9\pi[tan \frac{\pi}{3} - tan 0]](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20-%20tan%200%5D)
which yields:
]
I am ;-;
Doing a quiz right now- T^T
To get from the real value to the model value, you must divide by 21 and times by two (since 21/21 = 1 and 1 x 2= 2 in the ratio) this is the same as multiplying by the fraction 2/21.
So, 1.7 x 2/21 = 17/105 = 0.16m or 16cm
