Answer:
The original length was 41 inches and the original width was 16 inches
Step-by-step explanation:
Let
x ----> the original length of the piece of metal
y ----> the original width of the piece of metal
we know that
When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box
The dimensions of the box are

The volume of the box is equal to


so

simplify
-----> equation A
Remember that
The piece of metal is 25 in longer than it is wide
so
----> equation B
substitute equation B in equation A

solve for y

Solve the quadratic equation by graphing
using a graphing tool
The solution is y=16
see the attached figure
Find the value of x

therefore
The original length was 41 inches and the original width was 16 inches
Hi!
1in:4m
3in:xm
3/1 = 3
4 x 3 = 12
1in:4m
3in:12m
The answer is 12
Hope this helps! :)
Answer:
9.2
Step-by-step explanation:
The given triangle is a right angled triangle. To solve for any of the side length of such triangle, apply the trigonometry ratio formula which can easily be remembered as SOHCAHTOA.
SOH is Sin θ = opposite/hypothenuse,
CAH is Cos θ = Adjacent/hypotenuse
TOA is Tan θ = Opposite/adjacent
Thus, in the right triangle given, we have:
θ = 38°
Opposite side to the given angle = x
Hypotenuse = 15
We're going to use, sin θ = opposite/hypotenuse
Sin(38) = x/15
Multiply both sides by 15 to solve for x
15*sin(38) = x
15*0.616 = x
9.24 = x
<em>x ≈ 9.2 (to nearest tenth)</em>
Looks like a regular hexagon
see my attachment
we put some imaginary lines and take the 2 trignles on the right and put them on teh left side
now we have a rectangle wit height 8 and width 2+4 or 6
area=8*6=48 cm^2