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3 years ago

What is the common ratio in the geometric sequence? I need HELP. Thanks

Mathematics

1 answer:

attashe74 [19]3 years ago

5 0

Answer:

Step-by-step explanation:

Common ratio = 2nd term ÷ first term

$= \frac{35x^{2}}{5x}=\frac{35 * x * x}{5 *x}\\\\= 7x$

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What is the average of -30 -15 -20 55

defon

Answer:

-2.5

Step-by-step explanation:

-30 + (-15) + (-20) + 55 = -10. Then you divide it by how many numbers there are (4). Which equals - 2.5. If this is wrong, then round up to -3.

8 0

3 years ago

Read 2 more answers

What is the solution of the inequality x^3+3x^2>7x+6

sveta [45]

Answer:

x>2

Step-by-step explanation:

x3+3x2=7x+6

x3+3x2−(7x+6)=7x+6−(7x+6)

x3+3x2−7x−6=0

(x−2)(x2+5x+3)=0

x−2=0 or x2+5x+3=0

x=2 or x=−0.6972243622680054 or x=−4.302775637731995

x<−4.302776

−4.302776<x<−0.697224

−0.697224<x<2

x>2(Works in original inequality)

3 0

3 years ago

Serena is trying to become more environmentally conscious by making her own cleaning products. She researches different cleaners

astra-53 [7]

56 is the right answer

4 0

3 years ago

D(x)=(x^2-12x+20)/(3x)

krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

Explanation:

d(x) = $\frac{x^{2}-12x+20}{3x}$

= $\frac{(x-2)(x - 10)}{3x}$

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0

÷3 ÷3

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

(1/3)x - 4
3x) x² - 12x + 20
x²
-12x
-12x
20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4

6 0

3 years ago

0.7 is 10 times as much as

Neko [114]

0.7 is 10 times as much as 0.70

3 0

4 years ago