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Anuta_ua [19.1K]
3 years ago
5

What is the common ratio in the geometric sequence? I need HELP. Thanks

Mathematics
1 answer:
attashe74 [19]3 years ago
5 0

Answer:

7x

Step-by-step explanation:

Common ratio = 2nd term ÷ first term

= \frac{35x^{2}}{5x}=\frac{35 * x * x}{5 *x}\\\\= 7x

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Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
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Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
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3 years ago
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Answer:

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2 years ago
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Answer:

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Step-by-step explanation:

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Louis found two bakeries to provide bagels for his sub shop. The first bakery offers 350 bagels for $168.00 and the second baker
borishaifa [10]

Answer:

<h2>$352</h2>

Step-by-step explanation:

Find out the price of one bagel by dividing the price by the number of bagels:

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3 years ago
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