3 years ago

Twelve oranges cost $2.00. At the same rate, how many oranges can be bought for $5.00?

Mathematics

1 answer:

netineya [11]3 years ago

4 0

Answer:

30 oranges can be bought

Step-by-step explanation:

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A bag contains 20 pieces of candy. There are 8 grape peices, 7 cherry pieces, and 5 lemon pieces. part a says that one piece is

Alex787 [66]

Grape- 8/20 = 2/5 = 40%
cherry - 7/20 = 35%
lemon - 5/20 = 25%

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3 years ago

What multiplies to be 280 and adds to be negative 36

photoshop1234 [79]

The two numbers are -18+ 2√(11) and -18 -2√(11).

-18+ 2√(11)+ [-18 -2√(11)]= -36
[-18+ 2√(11)]* [-18 -2√(11)]= 280.

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3 years ago

Enrique charges $5 for every 1/5 hour he spends walking dogs.

azamat

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4 years ago

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3 years ago

Consider the function f(x) = 20/√x and its second-degree polynomial P2 (x) = 20 - 10(x-1) + 7.5(x-1)^2 at x=0.8. Compute the val

krok68 [10]

Answer:

$f (0.8) = 22.3607$ and $P_{2} (0.8) = 22.300$ .

Step-by-step explanation:

According to the statement, $f (x) = \frac{20}{\sqrt{x}}$ and $P_{2}(x) = 20 - 10 (x-1) + 7.5 (x-1) ^ 2$ . Based on these definitions, at $x=0.8$ produce:

$f (0.8) = \frac{20}{\sqrt {0.8}} = 22.3607$ . On the other hand, you have to:

$P_{2} (0.8) = 20 - 10 (0.8 -1) +7.5 (0.8 -1)^2$

$P_{2} (0.8) = 20 - 10 (-0.2) +7.5 (-0.2)^2 = 22.300$

Then, it can be affirmed that $f (0.8) = 22.3607$ and $P_{2} (0.8) = 22.300$ .

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4 years ago