Answer:
6 is answer...............
Answer:
0.234523452345 as a fraction equals 234523452345/1000000000000
Step-by-step explanation:
To write 0.234523452345 as a fraction you have to write 0.234523452345 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.
0.234523452345 = 0.234523452345/1 = 2.34523452345/10 = 23.4523452345/100 = 234.523452345/1000 = 2345.23452345/10000 = 23452.3452345/100000 = 234523.452345/1000000 = 2345234.52345/10000000 = 23452345.2345/100000000 = 234523452.345/1000000000 = 2345234523.45/10000000000 = 23452345234.5/100000000000 = 234523452345/1000000000000
Answer:
a) P ( E | F ) = 0.54545
b) P ( E | F' ) = 0
Step-by-step explanation:
Given:
- 4 Coins are tossed
- Event E exactly 2 coins shows tail
- Event F at-least two coins show tail
Find:
- Find P ( E | F )
- Find P ( E | F prime )
Solution:
- The probability of head H and tail T = 0.5, and all events are independent
So,
P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375
P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)
= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875
- The probabilities for each events are:
P ( E ) = 0.375
P ( F ) = 0.6875
- The Probability to get exactly two tails given that at-least 2 tails were achieved:
P ( E | F ) = P ( E & F ) / P ( F )
P ( E | F ) = 0.375 / 0.6875
P ( E | F ) = 0.54545
- The Probability to get exactly two tails given that less than 2 tails were achieved:
P ( E | F' ) = P ( E & F' ) / P ( F )
P ( E | F' ) = 0 / 0.6875
P ( E | F' ) = 0
It is a representation of a number
Answer:
x = 2, y = 6
Step-by-step explanation:
Δ WXY is equilateral ( 3 congruent angles ), then the sides are equal
WY = WX , that is
y - 1 = 5 ( add 1 to both sides )
y = 6
Δ WYZ is isosceles ( 2 congruent base angles ) then the legs are congruent
YZ = WY , that is
x + 3 = 5 ( subtract 3 from both sides )
x = 2
