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3 years ago

PLEASE HELP ASAP!!!!!!!! Find the value of the variables.

Mathematics

1 answer:

Korvikt [17]3 years ago

3 0

Answer:

g=79

h=55

j=75

Step-by-step explanation:

1. When a transversal intersects two parallel lines corresponding angles, angles that are located in the same relative position an intersection of transversal and two or more straight lines, are congruent. Therefore g=79.

2. Since the two lines are parallel same side interior angles are supplementary. This means they add up to 180. So to find h solve the equation h+125=180. Once solved you get 55.

3. Like question 2, these angles are same side interior and therefore supplementary. To find j solve the equation j+105=180, which gets j=75.

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irina [24]

Option D:

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

Solution:

Given expression is $\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)$ .

<u>To find the product of the expression:</u>

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)$

Multiply each term of the first term with each term of the 2nd term.

$=y^{2}\left(8 y^{2}+y+1\right) +3 y\left(8 y^{2}+y+1\right) +7\left(8 y^{2}+y+1\right)$

Using the exponent rule: $a^m \cdot a^n = a^{m+n}$

$=\left(8 y^{4}+y^3+y^2\right) +\left(24 y^{3}+3y^2+3y\right) +\left(56 y^{2}+7y+7\right)$

$=8 y^{4}+y^3+y^2+24 y^{3}+3y^2+3y+56 y^{2}+7y+7$

Arrange the terms with same power.

$=8 y^{4}+y^3+24 y^{3}+y^2+3y^2+56 y^{2}+7y+3y+7$

$=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

Hence option D is the correct answer.

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

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Aashi buys

adoni [48]

Bread rolls = BR
Ketchup = K
Sausages = S

2BR +1K + 3S = £10 - 45p
2BR + 1K + 3S = £9.55

2BR = 1.40 x 2 = £2.80
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£2.80 + £1.80 + 3S = £9.55
3S = £9.55 - £2.80 - £1.80
3S = £4.95
£4.95 / 3 = BR
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The answer is £1.65 for one pack of sausages

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