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Bad White [126]
3 years ago
15

How do you write 80% as a decimal?

Mathematics
2 answers:
jeka57 [31]3 years ago
8 0
It would be 80/100, move over two times, the decimal is 0.80
KatRina [158]3 years ago
4 0

Answer:

0.8

Step-by-step explanation:

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An odd number between 301 and 370 has three different digits. If the sum of its digits is five times the hundreds digit, find th
damaskus [11]
For the answer to the question above, <span> 
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
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5 0
3 years ago
Find an equation of the line perpendicular to the graph of 14x-7=1 that passes through the point at (-2,4)
wolverine [178]

we know that

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so

m1*m2=-1

Step 1

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we have

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so

the perpendicular will be parallel to the x-axis

Step 2

The equation of the line perpendicular to the given line is the y-coordinate of the given point

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the equation is

y=4

therefore

<u>the answer is</u>

y=4

see the attached figure to better understand the problem

5 0
3 years ago
What is the scientific notation of each number 6908100000
SVEN [57.7K]

Answer:

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Step-by-step explanation:

7 0
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You can model the entrance to a mine shaft using the equation
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y=-1/2 2 (x+4)(x+-4+

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solving for x

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4 0
3 years ago
Read 2 more answers
given the points a (-1,2) and (7,14), find the coordinates of the point p on directed line segment ab that partitions ab in the
Vinvika [58]
Check the picture below.

\bf \left. \qquad  \right.\textit{internal division of a line segment}&#10;\\\\\\&#10;a(-1,2)\qquad b(7,14)\qquad&#10;\qquad 1:3&#10;\\\\\\&#10;\cfrac{aP}{Pb} = \cfrac{1}{3}\implies \cfrac{a}{b} = \cfrac{1}{3}\implies 3a=1b\implies 3(-1,2)=1(7,14)&#10;\\\\&#10;-------------------------------\\\\&#10;{ P=\left(\cfrac{\textit{sum of "x" values}}{r1+r2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{r1+r2}\right)}

\bf -------------------------------\\\\&#10;P=\left(\cfrac{(3\cdot -1)+(1\cdot 7)}{1+3}\quad ,\quad \cfrac{(3\cdot 2)+(1\cdot 14)}{1+3}\right)&#10;\\\\\\&#10;P=\left( \cfrac{-3+7}{4}~,~\cfrac{6+14}{4} \right)

3 0
3 years ago
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