A regular hexagon is inscribed in a circle of radius 77 m. Find the length of a side of the hexagon.
1 answer:
Hi there!
We'll use the image below as a reference diagram. As you can see, the hexagon is divided into 6 triangles. And, one red line (center to point on the hexagon) would be the radius. Since we know that all of the triangles are equilateral triangles, and the hexagon is a regular hexagon, we know that one side of the hexagon is equal to 77m.
(If the circle actually has a diameter (all the way across the circle), the answer would be 38.5m)
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
We'll use the image below as a reference diagram. As you can see, the hexagon is divided into 6 triangles. And, one red line (center to point on the hexagon) would be the radius. Since we know that all of the triangles are equilateral triangles, and the hexagon is a regular hexagon, we know that one side of the hexagon is equal to 77m.
(If the circle actually has a diameter (all the way across the circle), the answer would be 38.5m)
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
You might be interested in
The factors of the quadratic equation is (x + 1) and (x - 6)
Given,
The quadratic equation; -2x² + 10x + 12
We have to find the factors of this equation using quadratic formula;-
Quadratic formula;-
Here,
a = -2, b = 10 and c = 12
Now,
=
=
= (-10±14) ÷ -4
Solve for,
- 10 + 14 / -4 = -4/4 = -1
That is, (x + 1)
Solve for,
- 10 - 14 / -4 = -24/-4 = 6
That is, (x - 6)
Therefore, the factors for the given quadratic equation is (x + 1) and (x - 6)
Learn more about quadratic formula here;
#SPJ1