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3 years ago

PLZ HELP ASAP!!!

Mathematics

1 answer:

dimulka [17.4K]3 years ago

5 0

C E makes a line.
B E does not make a line.
A F makes a line.
D E does not make a line.

Basically, if you see a line running through two points, it is a line.

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A color printer prints 29 pages in 12 minutes.<br> How many minutes does it take per page?

Julli [10]

Answer:

b b

Step-by-step explanation:v gv g

8 0

3 years ago

Read 2 more answers

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

2 years ago

K=mv^2/2 solve for v

matrenka [14]

Answer: $v=\sqrt[]{\frac{2K}{m} }$

Step-by-step explanation:

$K=\frac{mv^2}{2}$

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

$2*K=\frac{mv^2}{2}*2$

$2K=mv^2$

Divide by m to isolate $v^2$ .

$\frac{2K}{m}=\frac{mv^2}{m}$

$\frac{2K}{m} =v^2$

To eliminate the square and isolate v, extract the square root.

$\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}$

$\sqrt[]{\frac{2K}{m} }=v$

let's rewrite it in a way that v is in the left side.

$v=\sqrt[]{\frac{2K}{m} }$

4 0

2 years ago

How to graph 9x+5y=-45

lilavasa [31]

9x +5y= -45 put in standard form y= mx+b coefficient of x is the slope, b is the y intercpept 5y= -9x -45 y= -9/5 x -45 graphing will start at -45 on the y axis from that point go down 9 to the right 5 for the slope continue and graph minimum 2 points to draw the line hope this helps

8 0

3 years ago

BRAINLIEST TO FIRST ANSWER

NNADVOKAT [17]

Answer:

The mean is 70, that's all I know. Sorry!

Step-by-step explanation:

Here's how you find the mean:

1. Add together ALL NUMBERS. (which equals 560 in this case.)

2. DIVIDE by the amount of numbers there are. (So 560 ÷ 8 = 70)

3. There's your answer! The mean of these numbers is 70.

I really hope this helps! Have a great day\night!

6 0

3 years ago