What is the value of 6<br> 364<br> 484<br> 1.365<br> 1.456

Gabi wants to drive to and from the airport. She finds two companies near her that offer short-term car rental service at differ

lilavasa [31]

Answer:

The difference in per-mile costs for the two companies is $0.12

Step-by-step explanation:

Gabi sets up the equation $0.22m+7.20=0.1m+8.40$ to find out after how many miles, m, the companies will charge the same amount.

The first company charges $c_1=0.22m+7.20$ for m miles driven.

The second company charges $c_2=0.1m+8.40$ for m miles driven.

In both these functions, numbers 7.20 and 8,40 represent the initial fee the companies charge.

Numbers 0.22 and 0.1 represent per-mile costs.

Thus, the difference in per-mile costs is $0.22-0.1=0.12$

Another way to solve this problem is to find the cost per mile driven for each company:

1. Cost per-mile 1st company

$c_1(0)=0.22\cdot 0+7.20=7.20\\ \\c_1(1)=0.22\cdot 1+7.20=7.42\\ \\c_1(1)-c_1(0)-7.42-7.20=0.22$

2. Cost per-mile 2nd company

$c_2(0)=0.1\cdot 0+8.40=8.40\\ \\c_2(1)=0.1\cdot 1+8.40=8.50\\ \\c_2(1)-c_2(0)=8.50-8.40=0.1$

3. Difference:

$0.22-0.1=0.12$

6 0

3 years ago

Rina wants to run a karaoke machine for a family reunion. The prices to rent the machine from two different companies are shown

almond37 [142]

Sorry confused cant answer this one IDK

8 0

3 years ago

HELP PLEASE!!!!Decide if the function is an exponential function. If it is, state the initial value and the base.

soldi70 [24.7K]

Answer:

it is not an exponential function.

5 0

3 years ago

You want to test if more than 20% of homes in a neighborhood have recently been sold through a short sale, at a foreclosure auct

Elodia [21]

Answer:

We need to conduct a hypothesis in order to test the claim that more than 20% of homes in a neighborhood have recently been sold through a short sale, at a foreclosure auction, or by the bank following an unsuccessful foreclosure auction, so then the correct system of hypothesis are:

Null hypothesis: $p \leq 0.2$

Alternative hypothesis: $p > 0.2$

Step-by-step explanation:

Data given and notation

n=60 represent the random sample taken

X=14 represent the neighborhood that have recently been sold through a short sale, at a foreclosure auction, or by the bank following an unsuccessful foreclosure auction

$\hat p=\frac{14}{60}=0.233$ estimated proportion of neighborhood that have recently been sold through a short sale, at a foreclosure auction, or by the bank following an unsuccessful foreclosure auction

$p_o=0.2$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that more than 20% of homes in a neighborhood have recently been sold through a short sale, at a foreclosure auction, or by the bank following an unsuccessful foreclosure auction, so then the correct system of hypothesis are:

Null hypothesis: $p \leq 0.2$

Alternative hypothesis: $p > 0.2$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

8 0

4 years ago

An article in a magazine discussed the length of time till failure of a particular product. At the end of theâ product's lifetim

diamong [38]

Answer:

Step-by-step explanation:

From the missing information;

Lets assume that;

$\text{the exponential distribution mean = 500 thousand naira}$

$\text{Range 100 thousand}$ → $\text{1 million naira}$

∴

a)

$X \sim exp (\dfrac{1}{500}) \\ \\ P( X \le x) = 1 - e^{\dfrac{-x}{500}} \\ \\ P(X < 700) = 1 - e^{\frac{-7}{5}} \\ \\ \mathbf{P(X< 700) = 0.75340}$

b)

$Y \sim \cup (100,1000) \implies P(Y \le y ) = \dfrac{y - 100}{1000-100} \\ \\ P(Y < 700) = \dfrac{600}{900} = 0.67$

c)

$P(X < 830)= 1 - e^{\frac{-830}{500}} \\ \\ P(X < 830)= 1 - 0.1901 \\ \\ P(X < 830)=0.8099 \\ \\ P(Y < 830) = \dfrac{730}{900} = 0.8111 \\ \\ Thus;\mathbf{ P(X < 0.8099) = P(Y< 0.8111)}$

4 0

3 years ago

What is the value of 6 364 484 1.365 1.456