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ValentinkaMS [17]
3 years ago
13

In automobile mileage and gasoline-consumption testing, 13 automobiles were road tested for 300 miles in both city and highway d

riving conditions. The following data were recorded for miles-per-gallon performance.City: 16.2 16.7 15.9 14.4 13.2 15.3 16.8 16.0 16.1 15.3 15.2 15.3 16.2 Highway: 19.4 20.6 18.3 18.6 19.2 17.4 17.2 18.6 19.0 21.1 19.4 18.5 18.7 Use the mean, median, and mode to make a statement about the difference in performance for city and highway driving.
Mathematics
1 answer:
Aneli [31]3 years ago
6 0

Answer:

Looking at the mean, the median and the mode, cars are more efficient on a highway than in a city

Step-by-step explanation:

First, we calculate the average (mean) performance by adding all values and dividing the sum by the number of values added.

Mean_{city} =\frac{(16.2+16.7+15.9+14.4+13.2+15.3+16.8+16.0+16.1+15.3+15.2+15.3+16.2)mpg }{13} =15.6 mpg

Mean_{highway} =\frac{(19.4+20.6+18.3+18.6+19.2+17.4+17.2+18.6+19.0+21.1+19.4+18.5+18.7 )mpg }{13} =18.9 mpg

Then, to know what the median is, we have to order from least to greatest and look the middle value, i.e. half of the values will be higher than the median and half will be lower.

For the mode, we have to look up what is the most repeated value in our list.

For city performances:

  1. 13.2
  2. 14.4
  3. 15.2
  4. 15.3
  5. 15.3
  6. 15.3
  7. 15.9
  8. 16
  9. 16.1
  10. 16.2
  11. 16.2
  12. 16.7
  13. 16.8  

The median value is 15.9 miles per gallon, and the mode is 15.3 miles per gallon.

For highway performances:

  1. 17.2
  2. 17.4
  3. 18.3
  4. 18.5
  5. 18.6
  6. 18.6
  7. 18.7
  8. 19
  9. 19.2
  10. 19.4
  11. 19.4
  12. 20.6
  13. 21.1

The median value is 18.7 miles per gallon, and the mode is 18.6 and 19.4 miles per gallon.

We can say then, that looking at the mean, the median and the mode, cars are more efficient on a highway than in a city and that the least-consuming car in a city still is worst  in terms of efficiency than the worst-performing in a highway.

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Can anyone help me set up a system of equations for these problems??
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Answer:

L = the length of the field

W = the width of the field

The First Question:

The system is: L - 12 = w

                         2L + 2W = 76

Plug in L - 12 for W and you will get

2L + 2L - 24 = 76

4L -24 = 76

4L = 100

L = 25

To find W do L - 12 = w

25 - 12 = w

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Equals 6 1/2

Step-by-step explanation:

You need to add 3 and 2 first. then Put 5 over 6 and 2 over 3 and add them together

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Consider the equality xy k. Write the following inverse proportion: y is inversely proportional to x. When y = 12, x=5.​
skelet666 [1.2K]

Answer:

y=\dfrac {60} {x}   or   xy=60   (depending on your teacher's format preference)

Step-by-step explanation:

<h3><u>Proportionality background</u></h3>

Proportionality is sometimes called "variation".   (ex. " 'y' varies inversely as 'x' ")

There are two main types of proportionality/variation:

  1. Direct
  2. Inverse.

Every proportionality, regardless of whether it is direct or inverse, will have a constant of proportionality (I'm going to call it "k").

Below are several different examples of both types of proportionality, and how they might be stated in words:

  • y=kx      y is directly proportional to x
  • y=kx^2     y is directly proportional to x squared
  • y=kx^3     y is directly proportional to x cubed
  • y=k\sqrt{x}}   y is directly proportional to the square root of x
  • y=\dfrac {k} {x}   y is inversely proportional to x
  • y=\dfrac {k} {x^2}   y is inversely proportional to x squared

From these examples, we see that two things:

  • things that are <u>directly proportional</u> -- the thing is <u>multipli</u>ed to the constant of proportionality "k"
  • things that are <u>inversely proportional</u> -- the thing is <u>divide</u>d from the constant of proportionality "k".

<h3><u>Looking at our question</u></h3>

In our question, y is inversely proportional to x, so the equation we're looking at is the following y=\dfrac {k} {x}.

It isn't yet clear what the constant of proportionality "k" is for this situation, but we are given enough information to solve for it:  "When y=12, x=5."

We can substitute this known relationship pair, and find the "k" that relates this pair of numbers:

<h3><u>Solving for k, and finding the general equation</u></h3>

General Inverse variation equation...

y=\dfrac {k} {x}

Substituting known values...

(12)=\dfrac {k} {(5)}

Multiplying both sides by 5...

(12)*5= \left ( \dfrac {k} {5} \right ) *5

Simplifying/arithmetic...

60=k

So, for our situation, k=60.  So the inverse proportionality relationship equation for this situation is y=\dfrac {60} {x}.

The way your question is phrased, they may prefer the form: xy=60

7 0
2 years ago
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