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3 years ago

Which set Paris does not show y as a function of x?

Mathematics

1 answer:

Alex17521 [72]3 years ago

3 0

Answer:

Step-by-step explanation:

the x coordinations can not repeat as it does in option c so c is the answer

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A copy waa made of sallys photograph. The copy resized the photograph so that it measured 4 inches wide by 8 inches long. If the

Rashid [163]

Answer:

Step-by-step explanation:

5 0

3 years ago

How do you solve for x <br><br>the similarity statement is abc~ xyz

tensa zangetsu [6.8K]

Answer:

m<X= 36.87 degrees

Step-by-step explanation:

Since the triangle abc and xyz are similar, hence;

m<C = m<Y

90 = x - 5

Add 5 to both sides

90+5 = x-5+5

95 = x

Swap

x = 95

m<Y = x - 5

m<Y = 95 - 5

m<Y = 90

Find m<X

Using the SOH CAH TOA

Opposite to m<X = YZ = 6

Adjacent = 8

Tan M<X = opp/adj

Tan m<X = 6/8

m<X = arctan(6/8)

m<X= 36.87 degrees

8 0

3 years ago

Daniel invests $2,037 in a retirement account with a fixed annual interest rate of 6% compounded 6 times per year. What will the

notka56 [123]

Answer:

$\$5294.72$

Step-by-step explanation:

GIVEN: Daniel invests $\$2,037$ in a retirement account with a fixed annual interest rate of $6\%$ compounded $6$ times per year.

TO FIND: What will the account balance be after $16$ years

SOLUTION:

Amount invested by Daniel $=\$2037$

Annual interest rate $=6\%$

Total amount generated by compound interest is $=P(1+\frac{r}{n})^n^t$

Here Principle amount $P=\$2037$

rate of interest $r=6\%$

number of times compounding done in a year $n=6$

total duration of time $nt=16\text{ years}$

putting values we get

= $2037(1+\frac{6}{6\times100})^1^6$

$=2037(\frac{101}{100})^1^6$

$=\$5294.72$

Hence the total balance after $16\text{ years}$ will be $\$5294.72$

4 0

3 years ago

Solve irrational equation pls

rusak2 [61]

$\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\
x(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\\
(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle3,\infty)$

$
\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\
2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
\sqrt{(x^2+x-2)(x^2-4x+3)}=\dfrac{-x^2+3x-2}{2}\\
(x^2+x-2)(x^2-4x+3)=\left(\dfrac{-x^2+3x-2}{2}\right)^2\\
(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\$
$
4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\\
(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\\
(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\\
(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\\
(x-1)^2(3x^2-28)=0\\
x-1=0 \vee 3x^2-28=0\\
x=1 \vee 3x^2=28\\
x=1 \vee x^2=\dfrac{28}{3}\\
x=1 \vee x=\sqrt{\dfrac{28}{3}} \vee x=-\sqrt{\dfrac{28}{3}}\\$

There's one more condition I forgot about
$-(x-2)(x-1)\geq0\\
x\in\langle1,2\rangle\\$

Finally
$x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{\dfrac{28}{3}}, -\sqrt{\dfrac{28}{3}}\}\\
\boxed{\boxed{x=1}}$

3 0

3 years ago

Solve by Substitution. <br> 3x+2y=-4 <br> y=4x-2

qwelly [4]

x=0

y=-2

You'd put them in an ordered point, so (0,-2).

8 0

3 years ago

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Which set Paris does not show y as a function of x?​

Which set Paris does not show y as a function of x?