Answer:
The Pythagorean theorem states that a2 + b2 = c2 in a right triangle where c is the longest side. You can use this equation to figure out the length of one side if you have the lengths of the other two.
Hello!
Ignore the negative and solve the square root which is 13.
Add the negative with 13 you get -13
Special case is when it is square root of -169 then it will involved with i.
But for this question just solve it directly.
Have a great day!
Hello
the equation is y = ax+b
a the slop a = 4
y = 4x+b
the line <span>passes through (3, -10) : -10 = 6(3)+b
b = -28
</span>the equation is y = 6x-28
Step-by-step explanation:
1. Use the Pythagorean theorem to solve for side KM:
- 16^2+KM^2=34^2
- 256+KM^2=1156
- KM^2=900
- KM=30
2. Cosine is adjacent over hypotenuse, so cosine of M would be KM/34, or 30/34
3. Tangent is opposite over adjacent, so tangent of L will be KM/16, or 30/16
4. Sine is opposite over hypotenuse, so sine of M will be 16/34
5. KM=30, solved for in step 1.
hope this helps!!
Answer:
1) X stands for individual acts and y, group acts. 2) Each scenario describes a different period in minutes, but each one respecting their different amounts (individual and group acts). 3) 
Step-by-step explanation:
Completing with what was found:
<em> 1) Here is a summary of the scenario your classmate presented for the talent show:Main show The main show will last two hours and will include twelve individual acts and six group acts.Final show The final show will last 30 minutes and will include the top four individual acts and the top group act.The equations he came up with are: 12x+ 6y= 120, 4x+ y= 30</em>
1. What do x and y represent in this situation?
X stands for individual acts and y, group acts.
Besides that, In the system of equation, they represent the time for x, and the time for y.
2. Do you agree that your classmate set up the equations correctly? Explain why or why not.
Yes, that's right. Each scenario describes a different period in minutes, but each one respecting their different amounts (individual and group acts). Either for 120 minutes or 30 minutes length. And their sum totalizing the whole period.
3. Solving the system by Elimination
