I dont have options but i can sayEach of these questions is asking you to figure out how g(x) would be graphed based on some other function, f(x), except we're gonna make some changes to f(x) first. For example, let's look at part (a). You're told that g(x) = 2f(x)+3. 1. Whatever f(x) is, 2f(x) would take all of the y values and double them.2. Whatever that turns out to be, "+3" would add 3 to every y value. So, to translate (1, -2), first we double the y value...so that'd be -2 * 2, or -4. Then we add 3, which gives 1. So, the point (1, -2) becomes (1, 1). [EDIT: Um, no, -4 + 1 isn't 1. It's -1. My bad! MBW] Part (b) is a little bit trickier: 1. Whatever f(x) is, by adding 1 to x, it actually shifts the graph left by 1, even though it sorta feels like you should be shifting it 1 to the right. Let's not get too far into the details here, so for the moment, f(x+1) means "shift the graph of f to the left by 1." In other words, subtract 1 from x to get the new point. 2. Whatever f(x+1) is, then the "-3" would subtract 3 to every y value. So, if (1, -2) was on the original graph, then f(x+1) would be shifted to the left by 1...so that's (0, -2). And then, we subtract 3 from y, so that'd be (0, -5). Basically, anything inside the parentheses, like f(x+1), messes with the x coordinate of the point, and anything outside the parentheses, like -f(x) or f(x) + 3, messes with the y coordinate. For the last two, I'll give you a few hints and see if you can take it from there. For part (c): f(2x), even though you think it might double the value of x, actually divides the value of x by 2.For part (d): the trick here is to ignore the "-x" until the last step. Deal with the f(x-1) first (which shifts the x coordinate...which way?), then the negative outside of f(x) (which flips the sign of the y coordinate), then the +3 outside of f(x)...and then, at the end, the "-x" would flip the sign of the x coordinate. I hope this helps point you in the right direction!
Answer:
Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
The option is
4. 270≤Ф≤360
Step-by-step explanation:
When the terminal arm of an angle starts from the x-axis in the anticlockwise direction then the angles are always positive angles.
For Example.
Quadrant I - 0 to 90°
Quadrant II - 90° to 180°
Quadrant III - 180° to 270°
Quadrant IV - 270° to 360° ( 4. 270≤Ф≤360 )
Hence,Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
When the terminal arm of an angle starts from the x-axis in the clockwise direction than the angles are negative angles.
Quadrant IV - 0° to -90°
Quadrant III - - 90° to -180°
Quadrant II - -180° to -270°
Quadrant I - -270° to -360°
Answer:
13, 22, 25, 28
Step-by-step explanation:
Just fill in x values as values given in equation
