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notka56 [123]
3 years ago
5

A package of tickets for four home game costs 180$. What proportion can you write to find what 12-game package costs if all indi

vidual tickets have the same price?
Mathematics
1 answer:
Sophie [7]3 years ago
6 0
"21 lol jfhfhdhdhhhhhhh"
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For options A– E choose all of the expressions that are equivalent to 3(4x + 3).
Katen [24]
3(4x+3) = 12x + 9
A= 3(4x+1)
B= 9 + 12x
C= 7x + 6
D= 12x + 9
E= 12x + 9

Answer: D, E

Hope This Helps✨
3 0
3 years ago
Which parabola has the graph shown?
ryzh [129]

The vertex is (-1, 2).

The equation of parabola:

x=(x-k)^2+h where (h, k) is the vertex

We have h = -1 and k = 2.

Substitute:

x=(y-2)^2-1\ \ \ \ |+1\\\\(x+1)=(y-2)^2

5 0
3 years ago
Evaluate 81.4 % of 58.81 km Give your answer rounded to 2 DP.
snow_lady [41]

Answer:

47.87

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3 years ago
How many different combinations are possible if each lock contains the numbers 0 to 39, and each combination contains three dist
Georgia [21]
(e) Each license has the formABcxyz;whereC6=A; Bandx; y; zare pair-wise distinct. There are 26-2=24 possibilities forcand 10;9 and 8 possibilitiesfor each digitx; yandz;respectively, so that there are 241098 dierentlicense plates satisfying the condition of the question.3:A combination lock requires three selections of numbers, each from 1 through39:Suppose that lock is constructed in such a way that no number can be usedtwice in a row, but the same number may occur both rst and third. How manydierent combinations are possible?Solution.We can choose a combination of the formabcwherea; b; carepair-wise distinct and we get 393837 = 54834 combinations or we can choosea combination of typeabawherea6=b:There are 3938 = 1482 combinations.As two types give two disjoint sets of combinations, by addition principle, thenumber of combinations is 54834 + 1482 = 56316:4:(a) How many integers from 1 to 100;000 contain the digit 6 exactly once?(b) How many integers from 1 to 100;000 contain the digit 6 at least once?(a) How many integers from 1 to 100;000 contain two or more occurrencesof the digit 6?Solutions.(a) We identify the integers from 1 through to 100;000 by astring of length 5:(100,000 is the only string of length 6 but it does not contain6:) Also not that the rst digit could be zero but all of the digit cannot be zeroat the same time. As 6 appear exactly once, one of the following cases hold:a= 6 andb; c; d; e6= 6 and so there are 194possibilities.b= 6 anda; c; d; e6= 6;there are 194possibilities. And so on.There are 5 such possibilities and hence there are 594= 32805 such integers.(b) LetU=f1;2;;100;000g:LetAUbe the integers that DO NOTcontain 6:Every number inShas the formabcdeor 100000;where each digitcan take any value in the setf0;1;2;3;4;5;7;8;9gbut all of the digits cannot bezero since 00000 is not allowed. SojAj= 9<span>5</span>
8 0
3 years ago
Write twenty-three thousandths in decimal form
bogdanovich [222]
0.023
if u divide 23 by one thousand you get 23 thousandths as a decimal
4 0
2 years ago
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