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BlackZzzverrR [31]
2 years ago
10

Peeps go look up egde rewies

Mathematics
2 answers:
Olegator [25]2 years ago
8 0

*shocking*

-runs in high heels-

-trips-

oh my! dear child..

soldi70 [24.7K]2 years ago
4 0

Answer:

:o

Step-by-step explanation:

what is it. I dont wanna risk it bc school wifi Imao

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F(x)=x^2+8x-10 find f(a)+5
Papessa [141]

Answer:

We conclude that:

f(a) + 5 = a² + 8a - 5

Step-by-step explanation:

Given

The function is given by

f(x) = x²+8x-10

To determine

f(a)+5

In order to determine f(a)+5, first, we need to determine f(a).

Now substitute x = a in the function f(x) = x²+8x-10

f(a) = (a)² + 8(a) - 10

f(a) = a² + 8a - 10

Thus,

f(a) + 5 = (a² + 8a - 10) + 5

f(a) + 5 = a² + 8a - 5

Therefore, we conclude that:

f(a) + 5 = a² + 8a - 5

4 0
2 years ago
URGENT URGENT helppps plz
Murljashka [212]

Answer:

1) Bigger sector = 168.8pi

1) Smaller sector = 56.3pi

2) Bigger sector = 529.9

3) Smaller sector = 176.6

Step-by-step explanation:

1) Bigger sector =  \frac{270}{360}×pi×15×15

                          = 168.75pi

1) Smaller sector = \frac{360-270}{360}×pi×15×15

                             = \frac{90}{360}×pi×15×15

                             = 56.25pi

2) Bigger sector =  \frac{270}{360}×3.14×15×15

                           = 529.875

2) Smaller sector = \frac{360-270}{360}×3.14×15×15

                             = \frac{90}{360}×3.14×15×15

                             = 176.625

6 0
2 years ago
Assume the competing hypotheses take the following form: H0: µ1 – µ2 = 0, HA: µ1 – µ2 ≠ 0, where µ1 is the population mean for p
DedPeter [7]

Answer:

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

Step-by-step explanation:

H0: µ1 – µ2 = 0

HA: µ1 – µ2 ≠ 0

We have given,

The population variances are not known and cannot be assumed equal.

The test statistic for the test is

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

Where,

\bar x_1 = sample meaan of population 1

\bar x_2 = sample mean of population 2

n_1 = sample size of population 1

n_2 = sample size of population 2

Therefore, this is the test

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

7 0
3 years ago
Anyone know this, if you do plz help me. If the octagon is cm wide what is the area?
DENIUS [597]

Answer:

92

Step-by-step explanation:

Corner triangle: 1/2 (2 x 2) = 2

4 triangles = 4 x 2 = 8

Octagon + 4 triangles forms a square: 10 x 10 = 100

Octagon: 100 - 8 = 92

3 0
3 years ago
This is part two of the questions
vodomira [7]

Answer:

Step-by-step explanation:

5 0
2 years ago
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