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zmey [24]
3 years ago
7

James has $32 and earns $10 per week for his allowance. What is the initial value for the scenario described? A.10 B.32 C.42 D.3

20
Mathematics
2 answers:
serious [3.7K]3 years ago
5 0

Is 32 and confirmed. Is asking what is the initial value and that means what was the amount he started with, which it says it started with $32.  The word INITIAL, is a key word to understand the word BEGINING!

vova2212 [387]3 years ago
4 0
I think it'll be 32$ cuz thats what he started with.
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3 0
3 years ago
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Whitepunk [10]

Answer:

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7. B. P 216.00

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13. A. Proportion

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Step-by-step explanation:

6. Mr. Bernard travels 5.12 km per hour on his bike. How far can he travel in 3.25 hours?

Speed = 5.12km/hr

Time = 3.25 hr

To find the distance;

Distance = speed * time

Distance = 5.12 * 3.25

Distance = 16.64 km

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Quantity = 48 pencils

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Total = quantity * cost price

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8. The Villaroel family bought a 125.65 square meter lot at P 4500.00 per square meter. How much did they

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9. What is 2.7/10 = 0.27

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11. A store owner has 63 kilograms of candy. If she puts the candy into 21 jars, how much candy will each jar

contain?

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7 0
3 years ago
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olchik [2.2K]
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4 0
3 years ago
A line passes through the point (-3,-3) and has a slope of 1/2 what is the equation of the line ?
Bezzdna [24]

Answer:

y = 1/2x -1.5

Step-by-step explanation:

The equation of a line is typically written as y = mx + b.

m is the slope of the line, while b is the y-intercept. y is the y-coordinate and x is the x-coordinate.

Since it indicated that the line has a slope of 1/2, we can substitute the m in the equation with 1/2.

y = 1/2x + b

In order to find the intercept of the line, we use the equation of a line to substitute the y-coordinate and x-coordinate of (-3,-3) to discover the y-intercept of b.

-3 = 1/2(-3) + b

One half of -3 is -1.5.

-3 = -1.5 + b

Add -1.5 to both sides of the equation.

-3 = -1.5 + b

+1.5  +1.5

-1.5 = b

Since we found the y-intercept, we can now place it into our equation.

y = 1/2x -1.5 and that's the answer!

7 0
3 years ago
Solve the given initial-value problem. x^2y'' + xy' + y = 0, y(1) = 1, y'(1) = 8
Kitty [74]
Substitute z=\ln x, so that

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dz}\cdot\dfrac{\mathrm dz}{\mathrm dx}=\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)

Then the ODE becomes


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which has the characteristic equation r^2+1=0 with roots at r=\pm i. This means the characteristic solution for y(z) is

y_C(z)=C_1\cos z+C_2\sin z

and in terms of y(x), this is

y_C(x)=C_1\cos(\ln x)+C_2\sin(\ln x)

From the given initial conditions, we find

y(1)=1\implies 1=C_1\cos0+C_2\sin0\implies C_1=1
y'(1)=8\implies 8=-C_1\dfrac{\sin0}1+C_2\dfrac{\cos0}1\implies C_2=8

so the particular solution to the IVP is

y(x)=\cos(\ln x)+8\sin(\ln x)
4 0
3 years ago
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