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3 years ago

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A plumber charges $25 to come to a home, and $50 per hour for a repair. Which equation gives the total cost, y, for a repair tha

t lasts x hours
a) 15x-25=y
b) 15x+25=y
c) 25x-15=y
d) 25x+15=y

2 answers:

Nata [24]3 years ago

5 0

Answer:

The total cost is given by equation

y = 25 + 50 x

Where y represents the total cost and x represents the hours he worked.

Step-by-step explanation:

Given : A plumber charges $25 to come to a home, and $50 per hour for a repair.

We have to determine the equation gives the total cost, y, for a repair that lasts x hours.

Since, given y represents the total cost

and x represents the hours he worked.

also, he charges $25 to come to a home,

and $50 per hour for a repair.

so , for x hours he charge 50 x

Thus, The total cost is given by equation

y = 25 + 50 x

Dmitry_Shevchenko [17]3 years ago

4 0

The answer is b)

15*x+25=y

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rosijanka [135]

Answer:

Option A. $y=0.28x+0.75$

Step-by-step explanation:

Let

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x ----> teaspoons of baking powder

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The formula to calculate the slope between two points is equal to

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$y-2.15=0.28x-1.4$

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3 years ago

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Express 17.5m in dm,cm,dam,mm,hm,km

Len [333]

Answer:

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Step-by-step explanation:

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andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$

Doing the operations inside of the brackets the derivatives are:

1 ) $(\frac{d((1/2)t^2)}{dt} )^2= t^2$

2) $\frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1$

Entering these values of the integral is

$r(t)= \int\limits^{16}_{0} \sqrt{t^2 +2t+1} dt$

It is possible to factorize the quadratic function and the integral can reduced as,

$r(t)= \int\limits^{16}_{0} (t+1) dt= \frac{t^2}{2} + t$

Thus, evaluate from 0 to 16

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