((–7) + (3 + i)) - (2 - (6 + i)) =-9 + 9 i
Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer: 28x+15
Step-by-step explanation:
Answer:
2 tan0 have fun hope it helps you
Step-by-step explanation:
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<span>Bees see “primary colors” as blue, green and ultra violet. <span>They can distinguish yellow, orange, blue-green, violet, purple, as combinations of their three primary colors.</span></span>
