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almond37 [142]
3 years ago
5

Within the set of whole numbers , one set of numbers satisfies the recursive formula an=(an-1)^2-an-1, when a4=870 what are the

first two terms of the sequence?
Mathematics
2 answers:
andrew11 [14]3 years ago
8 0

Answer: 3 and 6 will be the first and second term of the given series respectively.

Explanation:  since it is given-  a_n=(a_{n-1} )^2-a_{n-1} and a_4=870

so, by replacing n by 4, we will get- a_4=a_3^2-a_3⇒870= a_3^2-a_3⇒ a_3^2-a_3-870=0

after solving this equation we will get, a_3= -29 and 30.

If a_3= -29, but it is not a whole number.

Thus,a_3=30 will be the value of third term of the given series.

Again, by applying the given condition a_n=(a_{n-1} )^2-a_{n-1}, a_2= 6 or -5 (not possible), so, a_2=6 will be the second term.

Similarly, a_1=3 or -2 but  we will go to the whole number.

Thus, a_1=3 will be the first term.

anygoal [31]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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