Within the set of whole numbers , one set of numbers satisfies the recursive formula an=(an-1)^2-an-1, when a4=870 what are the

Question

4 years ago

5

first two terms of the sequence?

2 answers:

andrew11 [14] · Answer 1 · 2022-01-01T03:14:16+03:00

Answer: 3 and 6 will be the first and second term of the given series respectively.

Explanation: since it is given- $a_n=(a_{n-1} )^2-a_{n-1}$ and $a_4=870$

so, by replacing n by 4, we will get- $a_4=a_3^2-a_3$ ⇒870= $a_3^2-a_3$ ⇒ $a_3^2-a_3-870=0$

after solving this equation we will get, $a_3= -29$ and 30.

If $a_3= -29$ , but it is not a whole number.

Thus, $a_3=30$ will be the value of third term of the given series.

Again, by applying the given condition $a_n=(a_{n-1} )^2-a_{n-1}$ , $a_2= 6$ or -5 (not possible), so, $a_2=6$ will be the second term.

Similarly, $a_1=3$ or -2 but we will go to the whole number.

Thus, $a_1=3$ will be the first term.

anygoal [31] · Answer 2 · 2022-01-01T05:14:22+03:00

4 0

Answer:

A

Step-by-step explanation: