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3 years ago

10

How many times will Anna need to fill the measuring cup to measure 78 7 8 cup of turnips? If Anna divides the ingredients equall

y into 4 pots, how many cups of onions will she need in each pot?

1 answer:

bagirrra123 [75]3 years ago

4 0

Answer:

Step-by-step explanation:

3 너 도넛

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How do I solve 6/2 + 8/3

Xelga [282]

Answer:

The solved given fractional expression is $\frac{17}{3}$

Therefore the given fractional expression becomes

$\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

Step-by-step explanation:

Given fractional expression is $\frac{6}{2}+\frac{8}{3}$

To solve the given fractional expression as below :

$\frac{6}{2}+\frac{8}{3}$

$=3+\frac{8}{3}$

$=\frac{3\times 3+8}{3}$

( here taking the term 3 as LCM )

$=\frac{9+8}{3}$ ( by adding the sums here )

$=\frac{17}{3}$

$\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

Therefore the solved given fractional expression is $\frac{17}{3}$

Therefore the given fractional expression becomes

$\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

The solved given fractional expression is $\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

7 0

3 years ago

HELLO CAN SOMEONE HELP ME IM FAILING MATH NO FAKE ANSWERS PLS TY :)

mixer [17]

Answer:

Area of rectangle = 10 units²

Area of triangle = 10 units²

Area of figure = 20 units²

Step-by-step explanation:

7 0

2 years ago

The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.

VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

$\int\limits^2_{-1} {(f(x) - g(x))} \, dx$

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx$

We know that:

$\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}$

$\int\limits^{}_{} {1} \, dx = x$

$\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}$

Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

The right side is equal to:

$(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6$

The bounded area is 5 + 5/6 square units.

3 0

2 years ago

What is the value of x?

nirvana33 [79]

Answer:

25

Explanation:

By Using Pythagoras Theorem,

h^2=p^2+b^2

or, x^2=(24)^2+7^2

or, x^2=576+49

or, x^2=625

or, x=√625

•°• x=25

8 0

2 years ago

Define binary operation.

grandymaker [24]

a mathematical operation, such as addition or multiplication, performed on two elements of a set to derive a third element.

5 0

3 years ago