3 years ago

What is the domain and range?

Mathematics

1 answer:

Savatey [412]3 years ago

4 0

Domain sets values and Range is the difference between the highest and the lowest numbers.

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If A = {1, 2, 3} the number of non-empty proper subsets are

Ksenya-84 [330]

Answer:

The number of non empty proper subsets of a set with 3 elements is =23−2=8−2=6.

4 0

3 years ago

What is the answer to this question ? 3a-4=5

Nataly_w [17]

Answer:

a=3

Step-by-step explanation:

a=3 because 5+4=9 and 9÷3=3

hope this helps!!

8 0

3 years ago

Read 2 more answers

PLEASE HELP!!

irina [24]

Answer:

$\leadsto make \: y \: subject \\ - 3y + 2x = 5y - 8 \\ - 3y - 5y = - 2x - 8 \\ y( - 3 - 5) = - 2x - 8 \\ - 8y = - 2x - 8$

divide through out by -8 :

${ \boxed{ \boxed{y = \frac{1}{4} x + 1}}}$

Answer is b

3 0

3 years ago

The piggy bank contains 16 dimes, 8 nickels, and 12 quarters. This morning you removed 3 dimes and 5 nickels.Which expression co

Bond [772]

16•0.10= 1.60$
8•0.05= 0.40¢
12•0.25= 3.00$

1.60$+0.40¢+3.00$= 5.00$

3•0.10= 0.30¢
5•0.05= 0.25¢

0.30¢+0.25¢= 0.55¢

5.00$-0.55¢= 4.45$

4.45$ is left in the piggy bank.

3 0

3 years ago

Determine whether each function is continuous at x=5. Justify your answer using the continuity test.

irakobra [83]

Answer:

2. $f(x)=\frac{x^2}{x+5}$

Step-by-step explanation:

When you replace x=5 into those functions you obtain:

$1. f(x)=\sqrt{x^2-36} = \sqrt{5^2-36} = \sqrt{-11} \\2. f(x)=\frac{x^2}{x+5}=\frac{5^2}{5+5}=\frac{25}{10}$

We can see that the function number 1, when the x=5 is replaced, falls into the imaginary numbers or complex domain, so the function is not continuous in the real domain.

On the other hand, the second function falls into the real domain whe x=5 is replaced, so the function is continuous in the real domain!

I hope you understand!

6 0

3 years ago