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3 years ago

Simplify using the laws of exponents (4^3)^-2 × (2^3)^4 ×(8/15)^-2

Mathematics

1 answer:

katrin2010 [14]3 years ago

8 0

Answer:

$\dfrac{225}{64}$

Step-by-step explanation:

$(4^3)^{-2} \times (2^3)^4 \times (\dfrac{8}{15})^{-2} =$

$= (2^2)^{-6} \times 2^{12} \times (\dfrac{15}{8})^{2}$

$= 2^{-12} \times 2^{12} \times \dfrac{225}{64}$

$= \dfrac{225}{64}$

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3 years ago

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kirill [66]

Answer:

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Step-by-step explanation:

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Simplify using the laws of exponents (4^3)^-2 × (2^3)^4 ×(8/15)^-2​

Simplify using the laws of exponents (4^3)^-2 × (2^3)^4 ×(8/15)^-2