Simplify using the laws of exponents (4^3)^-2 × (2^3)^4 ×(8/15)^-2

Mathematics

1 answer:

katrin2010 [14]3 years ago

8 0

Answer:

$\dfrac{225}{64}$

Step-by-step explanation:

$(4^3)^{-2} \times (2^3)^4 \times (\dfrac{8}{15})^{-2} =$

$= (2^2)^{-6} \times 2^{12} \times (\dfrac{15}{8})^{2}$

$= 2^{-12} \times 2^{12} \times \dfrac{225}{64}$

$= \dfrac{225}{64}$

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The circumference of the equator of a sphere was measured to be 82 82 cm with a possible error of 0.5 0.5 cm. Use linear approxi

True [87]

Answer:

The maximum error in the calculated surface area is approximately 8.3083 square centimeters.

Step-by-step explanation:

The circumference ( $s$ ), in centimeters, and the surface area ( $A_{s}$ ), in square centimeters, of a sphere are represented by following formulas:

$A_{s} = 4\pi\cdot r^{2}$ (1)

$s = 2\pi\cdot r$ (2)

Where $r$ is the radius of the sphere, in centimeters.

By applying (2) in (1), we derive this expression:

$A_{s} = 4\pi\cdot \left(\frac{s}{2\pi} \right)^{2}$

$A_{s} = \frac{s^{2}}{\pi^{2}}$ (3)

By definition of Total Differential, which is equivalent to definition of Linear Approximation in this case, we determine an expression for the maximum error in the calculated surface area ( $\Delta A_{s}$ ), in square centimeters: