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3 years ago

A coordinate plane with a line passing through (negative 4, negative 4), (0, 0) and (4, 4).

Mathematics

2 answers:

antiseptic1488 [7]3 years ago

8 0

Answer:B

Step-by-step explanation: x - 1/2y = 0 just seems like the most reasonable answer.

Kisachek [45]3 years ago

5 0

Answer:

-x + y = 0 or x - y = 0

Step-by-step explanation:

The line passes through points (0, 0) and (4,4), then its slope is:

m = (4 - 0)/(4 - 0) = 1

Given that the line passes through (0, 0), its y-intercept is

b = 0

Using slope and y-intercept form:

y = mx + b

y = x

The standard form of a line is:

Ax + By = C

So, we have to put all variables on the left side, as follows:

-x + y = 0

Multiplying by (-1) at both sides:

x - y = 0

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What is the definition of slope

lbvjy [14]

Answer:

A slope is a surface of which one end or side is at a higher level than another

Step-by-step explanation:

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6 0

3 years ago

HELP!!!!!

Nata [24]

Answer:

Step-by-step explanation:

identify two points on the graph:

1. (0, 4)

2. (-2, 2)

use slope formula: (y² - y¹) / (x² - x¹)

1. (2 - 4) / (-2 - 0) = -2 / -2 = 1

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8 0

3 years ago

Read 2 more answers

Claire received 3/8 of her allowance on Monday. What decimal shows the part of her allowance that she received?

lakkis [162]

Answer:

0.375

Step-by-step explanation:

3/8 = 0.375

4 0

2 years ago

How would the mean change if the number 52 replaced the number 12 in the set?

m_a_m_a [10]

Answer:

increase

Step-by-step explanation:

First, we need to find the mean of the given data set without any change.

10 + 61 + 10 + 44 + 21 + 79 + 27 + 12 = 264

264 ÷ 8 = 33

Now that we have the mean, we can find the mean of the data set with the change of 52.

10 + 61 + 10 + 44 + 21 + 79 + 27 + 52 = 304

304 ÷ 8 = 38

From this, we can see that the mean has increased with the change of 12 to 52. Thus, that's the correct option.

hope this helps!

6 0

2 years ago

Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9

natulia [17]

Parameterize $C$ by

$\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle$

where $0\le t\le\pi$ . Then the line integral is

$\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt$
$=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt$
$=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt$

Take $u=\cos t$ , then

$=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du$
$=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du$
$=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du$
$=54$

6 0

3 years ago