for a minute i thought it was c. y = -3x + 2.
A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
4 ft for the windows +2 +1/2 for space betwn bottom of window and floor
4 +2.5 =6.5ft
Hi , the two numbers are 2 and 10 , 10 is 8 more than 2 and 10 +2=12.
If you can find your way through all the smoke of the definition,
you find that an increase of 10 times the intensity is an increase
of 10 dB.
Next, if you can find your way over, under, around, and through
all the speeds and distances of the vehicles, you'll find that you
don't need them. Right in the middle of the pile, it says "intensity
10 times that of ...". That right there tells you that the sound of
the truck is 10 dB louder than the sound of the car.
So the car is 70 dB (asked for, and then given), and the truck is 80 dB.
