Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

Hence the bounds of the interval are:
As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
More can be learned about the z-distribution at brainly.com/question/25890103
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Cannot be determined is the answer.
Answer:
C(t)=3000(1.002417)^12t+960t
if T=1 year then the saving will be : 4048.17
Step-by-step explanation:
3000 deposit amount, 2.9 compound monthly interest . save 80 dollars per month at home .
A=p(1+r)^t
A=3000(1+0.029/12)^12t
A=3000(1.002417)^12t dollars
for the amount saved at home=80*12t=960t dollars
C(t)=3000(1.002417)^12t+960t
if T=1 year then the saving will be :
C(t)=3000(1.002417)^12t+960t
=3088.17+960= 4048.17 dollars
Percent change = change/original * 100
(2.65 - 2.30)/ 2.65 * 100
.35/2.65 * 100
13.2 % decrease
-13.2% if you need to write is as a negative
Hello,
x^3-12x²-2x+24=x²(x-12)-2(x-12)=(x-12)(x²-2)
=(x-12)(x-√2)(x+√2)