Answer:
RYLAN MY MAAAN
Step-by-step explanation:
WASSOP WITH YOUR NAILS. her conclusion is not valid because it would last less
Fragment free frame processing method causes a switch to wait until the first 64 bytes of the frame have been received before forwarding the frame to the destination device
An advanced type of cut-through switching is fragment-free (runtless switching). Before making a switching choice, switches engaged in cut-through switching merely read the Ethernet frame's destination MAC address field.
- What distinguishes fragment-free switching from fast forward switching?
The latency in fast-forward mode is calculated between the first bit received and the first bit delivered. The most common cut-through switching technique is fast-forward switching. Switching without fragments: The switch stores the first 64 bytes of the frame in fragment-free switching before forwarding.
Learn more about frame here: brainly.com/question/19756844
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Answer: 4 / 663
Step-by-step explanation:
There are 4 queens in a deck of 52 cards.
Probability = 4/52 = 1/13
There are 4 sevens
Probability = 4/51
Total probability = 1/13 x 4/51 = 4 / 663
Answer:

From this result we can conclude that the value of 70.9 is 0.78 deviation below the true mean of 71.5 and that can be considered as unusual. If we conduct a hypothesis test or a confidence interval we will see that we have enough evidence to conclude that the true mean is not significantly different from 71.5.
Step-by-step explanation:
For this case from all the population we know that the population mean and deviation are:

And we take a random sample of size n =40 and we got a sample mean calculated with the following formula:

And we want to test if this value is unusually low.
Since the sample size is large n>30 we can use the central limit theorem who says that the distribution for the sample mean is given by:

And on this case if we replace the values that we have we got:

For this case we can calculate how many deviations above or below is our calculated value from the sample of size 40, using the z score given by:

From this result we can conclude that the value of 70.9 is 0.78 deviation below the true mean of 71.5 and that can be considered as unusual. If we conduct a hypothesis test or a confidence interval we will see that we have enough evidence to conclude that the true mean is not significantly different from 71.5.
Answer:
x= 1 y= -1
Step-by-step explanation:
Pick an equation to isloate x or y
5x+2y=3 becomes x=-2y+3/5
Subsitute that into second equation : 2(-2y+3y/5) + 3y=-1
Example and simplify.
Do the same to find x variable