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2 years ago

Estimate 416x9 then find thw product

Mathematics

1 answer:

Alla [95]2 years ago

4 0

3771,
Estimate: Calculate
Product: Answer
416 x 9 = 3771.

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Please help this is due in tommorow! I will mark you as brainliest!

pshichka [43]

Answer:

325.26

Step-by-step explanation:

that's the answer because you have to multiply the top

I have question do we have to do something to the bottom?

5 0

3 years ago

Solve for x -9<4x+3<27 enter your answer as one inequality in the box

ludmilkaskok [199]

If a< c< b then a<c and c<b

Separate the equation into 2 separate ones and solve them:

X-9 < 4x +3

Subtract 3 from both sides:

X-12 < 4x

Subtract x from both sides:

-12< 3x

Divide both sides by 3:

X > -4

4x+3 < 27

Subtract 3 from both sides

4x < 24

Divide both sides by 4

X <6

Combine to get one inequality:

-4<x<6

6 0

3 years ago

Select the two binomials that are factors of this trinomial x2+10x+16

Zigmanuir [339]

So for this trinomial, I will be factoring by grouping. Firstly, what two terms have a product of 16x^2 and a sum of 10x? That would be 8x and 2x. Replace 10x with 2x + 8x:

$x^2+2x+8x+16$

Next, factor x^2 + 2x and 8x + 16 separately. Make sure that they have the same quantity inside the parentheses: $x(x+2)+8(x+2)$

<u>Now you can rewrite this as $(x+8)(x+2)$ , which is your final answer.</u>

5 0

3 years ago

A chef uses 5 pounds of flour to bake 120 blueberry muffins.

azamat

B.
You have to find how much blueberry muffins you could make with one pound of flour.

4 0

3 years ago

Read 2 more answers

A spherical balloon is being inflated at a rate of 3 cubic inches per second. Determine the change in the rate of the radius.How

Novay_Z [31]

Answer:

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

The radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Consider the provided information.

A spherical balloon is being inflated at a rate of 3 cubic inches per second.

The volume of sphere is $V=\frac{4}{3}\pi r^3$

Differentiate the above formula with respect to time.

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

Substitute the respective values in the above formula,

$3=4\pi 6^2\frac{dr}{dt}$

$\frac{1}{48\pi}=\frac{dr}{dt}$

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

When d=16

$3=4\pi 8^2\frac{dr}{dt}$

$\frac{3}{256\pi}=\frac{dr}{dt}$

Thus, the radius is changing more rapidly when the diameter is 12 inches.

5 0

3 years ago