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sweet-ann [11.9K]
3 years ago
8

Estimate 416x9 then find thw product

Mathematics
1 answer:
Alla [95]3 years ago
4 0
3771,
Estimate: Calculate
Product: Answer
416 x 9 = 3771.
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2895÷229=<br> PLZ RIGHT WITH WHOLE NUMBER AND REMANDER<br> ---<br> R:
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Solve |2x- 6|&lt;10<br> O XI-2<br> O [xl-8<br> O x12
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Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

6 0
3 years ago
hi please help i’ll give brainliest if you give a correct answer (please show your long division on paper please :()
Vedmedyk [2.9K]

Answer:

Attached below

Step-by-step explanation:

sorry couldnt d it on paper ;)

3 0
3 years ago
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