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3 years ago

8

Answer ASAP i need help please

1 answer:

S_A_V [24]3 years ago

3 0

Answer:

This is basic math but ok.

A=2(lw+hw+lh)

A=2(24*8+12*8+24*12)

A=2(192+96+288)

A=2(576)

A=1152 square feet

second option on ur screen is the answer

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3 years ago

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Bayes' rule can be used to identify and filter spam emails and text messages. This question refers to a large collection of real

Blababa [14]

Answer:

0.134 = 13.4% probability that a message is spam, given that it contains the word "text" (or "txt")

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Contains the word "text", or "txt".

Event B: Spam message.

The word "text" (or "txt") is contained in of all messages, and in of all spam messages.

This means that $P(A) = 1$

747 of the 5574 total messages () are identified as spam. The word "text" (or "txt") is contained in all of them. So

$P(A \cap B) = \frac{747}{5574} = 0.134$

Then

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.134}{1} = 0.134$

0.134 = 13.4% probability that a message is spam, given that it contains the word "text" (or "txt")

5 0

4 years ago

Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

or

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

5 0

3 years ago

Read 2 more answers