24
Multiply 6 and 4 to get 24
They will be able to prepare 24 tables
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
Slope: (y2-y1)/(x2-x1)
(-3+2)/(-1+1) = -1/0 = undefined
The slope is undefined
F(x) = 3x^6 + 30x^5 +75x^4
Factoring 3x^4(x^2 +10x + 25) = 3x^4(x+5)(x+5) = 0
x = 0, -5 with -5 having a multiplicity of 2 are the zeroes.
