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bezimeni [28]
3 years ago
10

Find the measure of the indicated angle

Mathematics
2 answers:
scZoUnD [109]3 years ago
8 0
Answer: x = 76

Step-by-step explanation:
Hey there! I’m not fully sure because I don’t do geometry shapes of finding x angles but this is how I got x.

The left and bottom bases are the same. Let’s say that A will be the top point of the triangle b will be the bottom left corner angle and c would be in the bottom right corner. We can already see that ∠AB = ∠BC. Because we can see that one line between them. so that means 52* = A angle because of the side length

52 + 52 = 104
180 = total
104 = among angles (we know)
180 - 104 = 76
x = 76
just olya [345]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

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Help asap
IRINA_888 [86]

Answer:

3x^{3} (1+2x+3x^{3} )

Step-by-step explanation:

If you reverse the distributive property you would get something like this. You can double check if you want.

6 0
3 years ago
Read 2 more answers
What type of transformation is shown?
just olya [345]

Answer:

A Dilation

Step-by-step explanation:

your dilating the original shape to a new size

5 0
4 years ago
Read 2 more answers
Whats negative four times negative three halves?
horsena [70]
-4*-3/2
let's rewrite it
-4/1 * -3/2
since its multiplication you DO NOT need to find the lowest common denominator
just multiply across
-4 *-3 = 12
1*2= 2
so 12/2
is going to equal 6
8 0
3 years ago
I need this asap. Would appreciate for y’all help
steposvetlana [31]

Answer:

-3/2, -1

Step-by-step explanation:

Each coordinate contains one x value and one y value, (x,y).

If we work out the midpoint of each of these individually, it makes it much easier to find the midpoint of the line.

Let's take the x values first. Our first  x value is -4 and our second x value is 1. Imagine the integers between -4 and 1 laid out in a sequence:

-4, -3, -2, -1, 0, 1

If you take the middle value of this sequence, you get the midpoint of the x values.

In this case, the middle is between values -2 and -1, leaving us with a midpoint of -1.5. This as a fraction is -\frac{3}{2}.

Now let's look at the y values. Our first y value is 2 and our second y value is -4. Again, let's imagine those numbers laid out in a sequence:

2, 1, 0, -1, -2, -3, -4

Here, the middle of these values is -1, and this is the midpoint of the y values.

So if we put these two values in a coordinate, we get the midpoint of the line.

In this case, we get (-\frac{3}{2} ,-1).

5 0
2 years ago
√secA+tanA/√secA-tanA × √cosecA-1/√cosecA+1=1
Snowcat [4.5K]

Use:\\\\\sec A=\dfrac{1}{\cos A}\\\\\tan A=\dfrac{\sin A}{\cos A}\\\\\csc A=\dfrac{1}{\sin A}\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\---------------------------------\\\\\sec A+\tan A=\dfrac{1}{\cos A}+\dfrac{\sin A}{\cos A}=\dfrac{1+\sin A}{\cos A}\\\\\sec A-\tan A=\dfrac{1-\sin A}{\cos A}\\\\\csc A-1=\dfrac{1}{\sin A}-\dfrac{\sin A}{\sin A}=\dfrac{1-\sin A}{\sin A}\\\\\csc A+1=\dfrac{1+\sin A}{\sin A}


\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s

7 0
3 years ago
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