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Arada [10]
1 year ago
14

If you replace the outlier of 113°F with 100°F, what happens to the range? Why do you think this occurs?

Mathematics
1 answer:
Sedaia [141]1 year ago
8 0

If you replace the outlier of 113°F with 100°F, the the range changes from 42 degrees to 29 degrees.

<h3>What is the outlier about?</h3>

In the case above, by  replace the outlier of 113°F with 100°F, IQR will not change due to the fact that the q1 and q3 values are not influence by the outlier.

But the range will change from 42 degrees to 29 due to the fact that

113 - 71 = 42 and

100 - 71 =  29

Therefore, If you replace the outlier of 113°F with 100°F, the the range changes from 42 degrees to 29 degrees .

Learn more about outlier  from

brainly.com/question/3631910

#SPJ1

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For bone density scores that are normally distributed with a mean of 0 and a standard deviation of​ 1, find the percentage of sc
gogolik [260]

Answer:

a) The percentage of bone density scores that are significantly high is 2.28%

b) The percentage of bone density scores that are significantly low is 2.28%

c) The percentage of bone density scores that are not significant is 95.44%

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Problems of normally distributed samples are solved using the z-score formula.

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a. significantly high​ (or at least 2 standard deviations above the​ mean).

This is 1 subtracted by the pvalue of Z = 2.

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

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c. not significant​ (or less than 2 standard deviations away from the​ mean).

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Z = 2 has a pvalue of 0.9772

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95.44% of the scores are not significant

7 0
3 years ago
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