Answer is 1
.............
Answer:
paraell
Step-by-step explanation:
we are given

now, we can compare it with

we can find b
we get

now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8

b=1.6

b=1.4

b=1.2

now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
Answer:
write your question properly...
Answer:
The correct answer is -7.5 years.
Step-by-step explanation:
Given:
Principle amount = 12000
Interest = 4320
time = ?
rate = 4.8 simple interest
Solution:
We know that simple Interest I = (P*t*r)/100
then t = I*100/p*r
putting values in formula:
t = 4320*100/4.8*12000
= 432000/57,600
= 7.5 years