The sum of 43.9 and 4 groups of a number
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A rectangle has a perimeter of length + length + width + width.
L = length of the fence.
W = width of the fence.
so the perimeter will be L+L+W+W or 2L+2W or 2(L+W).
now, we know that 120 ⩽ 2(L+W).
we also know that 168 ⩾ 2(L+W)
and we also know that whatever the length is, is twice the width, or L = 2W.
L = length of the fence.
W = width of the fence.
so the perimeter will be L+L+W+W or 2L+2W or 2(L+W).
now, we know that 120 ⩽ 2(L+W).
we also know that 168 ⩾ 2(L+W)
and we also know that whatever the length is, is twice the width, or L = 2W.