Answer:
x is 2
Step-by-step explanation:
you need to do 10-6 is 4 then 2x? is 4
Step-by-step explanation:
-2w=9+7
-2w=16
w=16/-2
w=-8
Answer: (6a + 5b) • (6a - 5b)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "b2" was replaced by "b^2". 1 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(36 • (a2)) - 52b2
Step 2 :
Equation at the end of step 2 :
(22•32a2) - 52b2
Step 3 :
Trying to factor as a Difference of Squares :
3.1 Factoring: 36a2-25b2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 36 is the square of 6
Check : 25 is the square of 5
Check : a2 is the square of a1
Check : b2 is the square of b1
Factorization is : (6a + 5b) • (6a - 5b)
Final result :
(6a + 5b) • (6a - 5b)
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Answer with explanation:
For, a Matrix A , having eigenvector 'v' has eigenvalue =2
The order of matrix is not given.
It has one eigenvalue it means it is of order , 1×1.
→A=[a]
Determinant [a-k I]=0, where k is eigenvalue of the given matrix.
It is given that,
k=2
For, k=2, the matrix [a-2 I] will become singular,that is
→ Determinant |a-2 I|=0
→I=[1]
→a=2
Let , v be the corresponding eigenvector of the given eigenvalue.
→[a-I] v=0
→[2-1] v=[0]
→[v]=[0]
→v=0
Now, corresponding eigenvector(v), when eigenvalue is 2 =0
We have to find solution of the system
→Ax=v
→[2] x=0
→[2 x] =[0]
→x=0, is one solution of the system.
The given equation is :
1. The relationship such that dependent variable (y) is isolated is :
2. The table accompanying this equation :
3. graph of the given equation is in attachment ~
