<h2>
Answer:</h2>
The quadratic function are:
option: A A) y(y + 4) - y = 6
Option: C C.) 4b(b) = 0
<h2>
Step-by-step explanation:</h2>
We know that the general equation of a quadratic equation in terms of a variable x is given by:
A)
y(y + 4) - y = 6
On simplifying the terms we have:
Hence, option: A is correct.
B)
(3x + 2) + (6x - 1) = 0
Hence, it is a linear equation.
Hence, option: B is incorrect.
C)
4b(b) = 0
it could also be written as:
Hence, it is a quadratic equation.
Hence, option: C is correct.
D)
3a - 7 = 2(7a - 3)
which is again a linear equation.
Hence, option: D is incorrect.
Answer:
2k-3k+5
Step-by-step explanation:
If you're using the app, try seeing this answer through your browser: brainly.com/question/2989024——————————
You have
y as an implicit function of
x:
sin(xy) – x = 0Use implicit differentiation. As
y is a function of
x, then you must apply the chain rule there:
d d—— [ sin(xy) – x ] = —— (0) dx dx d d d—— [ sin(xy) ] – —— (x) = —— (0) dx dx dx d—— [ sin(xy) ] – 1 = 0 dx d—— [ sin(xy) ] = 1 dx dcos(xy) · —— (xy) = 1 dxNow, apply the product rule for that last derivative:
![\mathsf{cos(xy)\cdot \left[\dfrac{d}{dx}(x)\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\ \mathsf{cos(xy)\cdot \left[1\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\ \mathsf{y\,cos(xy)+x\,cos(xy)\cdot \dfrac{dy}{dx}=1}](https://tex.z-dn.net/?f=%5Cmathsf%7Bcos%28xy%29%5Ccdot%20%5Cleft%5B%5Cdfrac%7Bd%7D%7Bdx%7D%28x%29%5Ccdot%20y%2Bx%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%5Cright%5D%3D1%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7Bcos%28xy%29%5Ccdot%20%5Cleft%5B1%5Ccdot%20y%2Bx%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%5Cright%5D%3D1%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7By%5C%2Ccos%28xy%29%2Bx%5C%2Ccos%28xy%29%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%3D1%7D)
dyIsolate
—— :
dx dyx cos(xy) · —— = 1 – y cos(xy) dxAssuming
x cos(xy) ≠ 0,
dy 1 – y cos(xy)—— = ———————— <——— this is the answer.
dx x cos (xy)I hope this helps. =)
