Answer:
2n+7
Step-by-step explanation:
The answer to your question will be 15,625
Answer:
P(B | T)=3/13
Step-by-step explanation:
The question is missing the Venn diagram that shows the value of each variable.
From the Venn diagram we can see there are 10 paintings that not T and not B. That means the total number of paintings that either T or B is
P(T∪B) = 60-10= 50 paintings.
There are x(x-2) + x paintings from 20th century
P(T)= x(x-2) + x = x^2 - x
There are 2x+8 +x British paintings.
P(B)= 2x+8 +x = 3x +8
There are 2 paintings that both T and B
P(T∩B)= x
Using union equation we can find the x
P(T∪B) = P(T) + P(B) - P(T∩B)
50= x^2 - x + 3x +8 - x
x^2 + x + 8 - 50 = 0
x^2 + x + -42 =0
(x-6) (x+7)=0
x1= 6 x2=-7
Since x can't be minus, then x=6.
The question asking how much conditional probability that a random T paintings is also British. The calculation will be:
P(B|T)= P(B∩T) / P(B) = x/ (3x +8)= 6/(6*3+8)= 6/26= 3/13
arc length = pi /180 * angle in degree * radius
2 = pi/180 * 30 *r
2 = pi/6 *r
multiply by 6/pi
12/pi =r
3.819718634 =r
Answer: r =3.82 inches