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olga nikolaevna [1]
3 years ago
7

For -180°<θ<0 , which of the primary trigonometric functions may have positive values?

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0

Answer:

cos theta  = adj / hyp is positive (+/+)

Step-by-step explanation:

In this open interval, the hypotenuse (radius) is always positive, whereas the adjacent side is positive and the opposite side negative.

in this interval:

sin theta = opp / hyp is neg (-/+)

cos theta  = adj / hyp is positive (+/+)

tan theta = opp / adj = (-/+) :  negative

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Answer:

a) 7x words

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c) 15000 + 10x words

Step-by-step explanation:

The best way to do this would be to plug in real numbers to see how each situation would play out.  For example, for part a, let's say he learns 20 new words each day.  One week has seven days, so that would be 20 x 7, which is 140 words.  You multiply the # of days by the # of words, which is x.

For part b, if he tried to reach 1000 new words by doing 20 new words a day, you would find how long that would take by doing 1000 / 20, which would give you 500 days.  You divide the # of new words he's trying to reach by the # of words a day.

For part c, he already has a set # of new words that he's learned, and now he's just continuing the progress, so you start out with 15000, then add that to 10 new words a day multiplied by # of days (x).

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Answer:

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Step-by-step explanation:

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The population of a certain country in 1997 was 288 million people. In​ addition, the population of the country was growing at a
Crazy boy [7]

Answer:

a) In the year 1998 with 3 days, 2 hours, 44 minutes and 18.1006141 seconds

b) In the year 1998 with 19 days, 18 hours, 5 minutes and 35.10875472 seconds

Step-by-step explanation:

a) To know the time when the population will be 305 million people, we need to isolate the variable t in the equation, P(t)=288(1.009)^{t-1997}

So we isolate t with the property of logarithms that allow us go down the exponent, applying in both sides of the equation

For this subsection the value of P is equal to 305 million people

Ln(305)=Ln[(288)(1.009)]^{t-1997}

Ln(305)=(t-1997)*Ln[(288)(1.009)]

Now, we can isolate the value of t

\frac{Ln(305)}{Ln[(288)(1.009)]} =t-1997

\frac{Ln(305)}{Ln[(288)(1.009)]}-1997 =t

t=1998.008531776402

So to know the exact date we multiply the number after the point, that is 0.008531776402 for the number of days that have 1 year, equal to 365 days

0.008531776402*365= 3.114098387 days

then the number after the point, that is 0.114098387 will be multiply for the number of hours that have 1 day

0.114098387*24= 2.738361282 hours

then the number after the point, that is 0.738361282 will be multiply for the number of minutes that have 1 hour

0.738361282*60= 44.3016769 minutes

Finally, the number after the point, that is 0.3016769 will be multiply for the number of seconds that have 1 minute

0.3016769*60= 18.1006141 seconds

And we obtain that the time, when the population of the country is 305 million people, is in the year 1998 with 3 days, 2 hours, 44 minutes and 25.152 seconds

b) For calculate the time when the population is 395 million people, we do the same process we did in the subsection a)

Ln(395)=Ln[(288)(1.009)]^{t-1997}

Ln(395)=(t-1997)*Ln[(288)(1.009)]

Now, we can isolate the value of t

\frac{Ln(395)}{Ln[(288)(1.009)]} =t-1997

\frac{Ln(395)}{Ln[(288)(1.009)]}-1997 =t

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0.75387857 *24= 18.09308577 hours

0.09308577*60= 5.585145912 minutes

0.585145912*60= 35.10875472 seconds

And we obtain that the time, when the population of the country is 395 million people, is in the year 1998 with 19 days, 18 hours, 5 minutes and 35.10875472 seconds

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5/17(3/8) = 15/136

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